Whakaoti i te 1/a-b+e/a^2-b^2=

$$\frac { 1 } { a - b } + \frac { e } { a ^ { 2 } - b ^ { 2 } } =$$

Aromātai

$$\frac{a+b+e}{a^{2}-b^{2}}$$

Ngā Hipanga Rongoā Poto

Tauwehea te a^{2}-b^{2}.

$$\frac{1}{a-b}+\frac{e}{\left(a+b\right)\left(a-b\right)}$$

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Ko te taurea pātahi iti rawa o a-b me \left(a+b\right)\left(a-b\right) ko \left(a+b\right)\left(a-b\right). Whakareatia \frac{1}{a-b} ki te \frac{a+b}{a+b}.

$$\frac{a+b}{\left(a+b\right)\left(a-b\right)}+\frac{e}{\left(a+b\right)\left(a-b\right)}$$

Tā te mea he rite te tauraro o \frac{a+b}{\left(a+b\right)\left(a-b\right)} me \frac{e}{\left(a+b\right)\left(a-b\right)}, me tāpiri rāua mā te tāpiri i ō raua taurunga.

$$\frac{a+b+e}{\left(a+b\right)\left(a-b\right)}$$

Whakarohaina te \left(a+b\right)\left(a-b\right).

$$\frac{a+b+e}{a^{2}-b^{2}}$$

Kimi Pārōnaki e ai ki a

$$\frac{-a^{2}-2ab-2ea-b^{2}}{\left(a^{2}-b^{2}\right)^{2}}$$