Whakaoti i te 1/8x^2-7/8x-1=

$$\frac { 1 } { 8 } x ^ { 2 } - \frac { 7 } { 8 } x - 1 =$$

Tauwehe

$$\frac{\left(x-8\right)\left(x+1\right)}{8}$$

Ngā Upane Otinga

Tauwehea te \frac{1}{8}.

$$\frac{x^{2}-7x-8}{8}$$

Whakaarohia te x^{2}-7x-8. Whakatauwehea te kīanga mā te whakarōpū. Tuatahi, me tuhi anō te kīanga hei x^{2}+ax+bx-8. Hei kimi a me b, whakaritea tētahi pūnaha kia whakaoti.

$$a+b=-7 ab=1\left(-8\right)=-8$$

I te mea kua tōraro te ab, he tauaro ngā tohu o a me b. I te mea kua tōraro te a+b, he nui ake te uara pū o te tau tōraro i tō te tōrunga. Whakarārangitia ngā tau tōpū takirua pērā katoa ka hoatu i te hua -8.

$$1,-8 2,-4$$

Tātaihia te tapeke mō ia takirua.

$$1-8=-7 2-4=-2$$

Ko te otinga te takirua ka hoatu i te tapeke -7.

$$a=-8 b=1$$

Tuhia anō te x^{2}-7x-8 hei \left(x^{2}-8x\right)+\left(x-8\right).

$$\left(x^{2}-8x\right)+\left(x-8\right)$$

Whakatauwehea atu x i te x^{2}-8x.

$$x\left(x-8\right)+x-8$$

Whakatauwehea atu te kīanga pātahi x-8 mā te whakamahi i te āhuatanga tātai tohatoha.

$$\left(x-8\right)\left(x+1\right)$$

Me tuhi anō te kīanga whakatauwehe katoa.

$$\frac{\left(x-8\right)\left(x+1\right)}{8}$$

Aromātai

$$\frac{\left(x-8\right)\left(x+1\right)}{8}$$