Tauwehe
\frac{\left(a+2b\right)\left(a^{2}-2ab+4b^{2}\right)}{8}
Aromātai
\frac{a^{3}}{8}+b^{3}
Tohaina
Kua tāruatia ki te papatopenga
\frac{a^{3}+8b^{3}}{8}
Tauwehea te \frac{1}{8}.
\left(a+2b\right)\left(a^{2}-2ab+4b^{2}\right)
Whakaarohia te a^{3}+8b^{3}. Tuhia anō te a^{3}+8b^{3} hei a^{3}+\left(2b\right)^{3}. Ka taea te tapeke pūtoru te whakatauwehe mā te whakamahi i te ture: p^{3}+q^{3}=\left(p+q\right)\left(p^{2}-pq+q^{2}\right).
\frac{\left(a+2b\right)\left(a^{2}-2ab+4b^{2}\right)}{8}
Me tuhi anō te kīanga whakatauwehe katoa.
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