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\frac{5+\sqrt{2}}{\left(5-\sqrt{2}\right)\left(5+\sqrt{2}\right)}
Whakangāwaritia te tauraro o \frac{1}{5-\sqrt{2}} mā te whakarea i te taurunga me te tauraro ki te 5+\sqrt{2}.
\frac{5+\sqrt{2}}{5^{2}-\left(\sqrt{2}\right)^{2}}
Whakaarohia te \left(5-\sqrt{2}\right)\left(5+\sqrt{2}\right). Ka taea te whakareanga te panoni ki te rerekētanga o ngā pūrua mā te ture: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.
\frac{5+\sqrt{2}}{25-2}
Pūrua 5. Pūrua \sqrt{2}.
\frac{5+\sqrt{2}}{23}
Tangohia te 2 i te 25, ka 23.