Whakaoti i te 1/5x=10*4/5-2-x

$$\frac { 1 } { 5 } x = 10 \cdot \frac { 4 } { 5 } - 2 - x$$

Whakaoti mō x

$$x=5$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tuhia te 10\times \frac{4}{5} hei hautanga kotahi.

$$\frac{1}{5}x=\frac{10\times 4}{5}-2-x$$

Whakareatia te 10 ki te 4, ka 40.

$$\frac{1}{5}x=\frac{40}{5}-2-x$$

Whakawehea te 40 ki te 5, kia riro ko 8.

$$\frac{1}{5}x=8-2-x$$

Tangohia te 2 i te 8, ka 6.

$$\frac{1}{5}x=6-x$$

Me tāpiri te x ki ngā taha e rua.

$$\frac{1}{5}x+x=6$$

Pahekotia te \frac{1}{5}x me x, ka \frac{6}{5}x.

$$\frac{6}{5}x=6$$

Me whakarea ngā taha e rua ki te \frac{5}{6}, te tau utu o \frac{6}{5}.

$$x=6\times \frac{5}{6}$$

Me whakakore te 6 me te 6.

$$x=5$$