Whakaoti i te 1/4-2/3x=11/12

$$\frac { 1 } { 4 } - \frac { 2 } { 3 } x = \frac { 11 } { 12 }$$

Whakaoti mō x

$$x=-1$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tangohia te \frac{1}{4} mai i ngā taha e rua.

$$-\frac{2}{3}x=\frac{11}{12}-\frac{1}{4}$$

Ko te maha noa iti rawa atu o 12 me 4 ko 12. Me tahuri \frac{11}{12} me \frac{1}{4} ki te hautau me te tautūnga 12.

$$-\frac{2}{3}x=\frac{11}{12}-\frac{3}{12}$$

Tā te mea he rite te tauraro o \frac{11}{12} me \frac{3}{12}, me tango rāua mā te tango i ō raua taurunga.

$$-\frac{2}{3}x=\frac{11-3}{12}$$

Tangohia te 3 i te 11, ka 8.

$$-\frac{2}{3}x=\frac{8}{12}$$

Whakahekea te hautanga \frac{8}{12} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 4.

$$-\frac{2}{3}x=\frac{2}{3}$$

Me whakarea ngā taha e rua ki te -\frac{3}{2}, te tau utu o -\frac{2}{3}.

$$x=\frac{2}{3}\left(-\frac{3}{2}\right)$$

Me whakarea te \frac{2}{3} ki te -\frac{3}{2} mā te whakarea taurunga ki te taurunga me te tauraro ki te tauraro.

$$x=\frac{2\left(-3\right)}{3\times 2}$$

Me whakakore tahi te 2 i te taurunga me te tauraro.

$$x=\frac{-3}{3}$$

Whakawehea te -3 ki te 3, kia riro ko -1.

$$x=-1$$