Whakaoti i te 1/4(3-2x)-2>1/3x

$$\frac { 1 } { 4 } ( 3 - 2 x ) - 2 > \frac { 1 } { 3 } x$$

Whakaoti mō x

$$x<-\frac{3}{2}$$

Ngā Upane Otinga

Whakamahia te āhuatanga tohatoha hei whakarea te \frac{1}{4} ki te 3-2x.

$$\frac{1}{4}\times 3+\frac{1}{4}\left(-2\right)x-2>\frac{1}{3}x$$

Whakareatia te \frac{1}{4} ki te 3, ka \frac{3}{4}.

$$\frac{3}{4}+\frac{1}{4}\left(-2\right)x-2>\frac{1}{3}x$$

Whakareatia te \frac{1}{4} ki te -2, ka \frac{-2}{4}.

$$\frac{3}{4}+\frac{-2}{4}x-2>\frac{1}{3}x$$

Whakahekea te hautanga \frac{-2}{4} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 2.

$$\frac{3}{4}-\frac{1}{2}x-2>\frac{1}{3}x$$

Me tahuri te 2 ki te hautau \frac{8}{4}.

$$\frac{3}{4}-\frac{1}{2}x-\frac{8}{4}>\frac{1}{3}x$$

Tā te mea he rite te tauraro o \frac{3}{4} me \frac{8}{4}, me tango rāua mā te tango i ō raua taurunga.

$$\frac{3-8}{4}-\frac{1}{2}x>\frac{1}{3}x$$

Tangohia te 8 i te 3, ka -5.

$$-\frac{5}{4}-\frac{1}{2}x>\frac{1}{3}x$$

Tangohia te \frac{1}{3}x mai i ngā taha e rua.

$$-\frac{5}{4}-\frac{1}{2}x-\frac{1}{3}x>0$$

Pahekotia te -\frac{1}{2}x me -\frac{1}{3}x, ka -\frac{5}{6}x.

$$-\frac{5}{4}-\frac{5}{6}x>0$$

Me tāpiri te \frac{5}{4} ki ngā taha e rua. Ko te tau i tāpiria he kore ka hua koia tonu.

$$-\frac{5}{6}x>\frac{5}{4}$$

Me whakarea ngā taha e rua ki te -\frac{6}{5}, te tau utu o -\frac{5}{6}. I te mea he tōraro a -\frac{5}{6}, ka huri te ahunga koreōrite.

$$x<\frac{5}{4}\left(-\frac{6}{5}\right)$$

Me whakarea te \frac{5}{4} ki te -\frac{6}{5} mā te whakarea taurunga ki te taurunga me te tauraro ki te tauraro.

$$x<\frac{5\left(-6\right)}{4\times 5}$$

Me whakakore tahi te 5 i te taurunga me te tauraro.

$$x<\frac{-6}{4}$$

Whakahekea te hautanga \frac{-6}{4} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 2.

$$x<-\frac{3}{2}$$