Whakaoti i te 1/3(x-6)<x+8

$$\frac { 1 } { 3 } ( x - 6 ) < x + 8$$

Whakaoti mō x

$$x>-15$$

Ngā Upane Otinga

Whakamahia te āhuatanga tohatoha hei whakarea te \frac{1}{3} ki te x-6.

$$\frac{1}{3}x+\frac{1}{3}\left(-6\right)<x+8$$

Whakareatia te \frac{1}{3} ki te -6, ka \frac{-6}{3}.

$$\frac{1}{3}x+\frac{-6}{3}<x+8$$

Whakawehea te -6 ki te 3, kia riro ko -2.

$$\frac{1}{3}x-2<x+8$$

Tangohia te x mai i ngā taha e rua.

$$\frac{1}{3}x-2-x<8$$

Pahekotia te \frac{1}{3}x me -x, ka -\frac{2}{3}x.

$$-\frac{2}{3}x-2<8$$

Me tāpiri te 2 ki ngā taha e rua.

$$-\frac{2}{3}x<8+2$$

Tāpirihia te 8 ki te 2, ka 10.

$$-\frac{2}{3}x<10$$

Me whakarea ngā taha e rua ki te -\frac{3}{2}, te tau utu o -\frac{2}{3}. I te mea he tōraro a -\frac{2}{3}, ka huri te ahunga koreōrite.

$$x>10\left(-\frac{3}{2}\right)$$

Tuhia te 10\left(-\frac{3}{2}\right) hei hautanga kotahi.

$$x>\frac{10\left(-3\right)}{2}$$

Whakareatia te 10 ki te -3, ka -30.

$$x>\frac{-30}{2}$$

Whakawehea te -30 ki te 2, kia riro ko -15.

$$x>-15$$