Whakaoti i te 1/3*(x-1)-1=1/2*(x+1)

$$\frac { 1 } { 3 } \cdot ( x - 1 ) - 1 = \frac { 1 } { 2 } \cdot ( x + 1 )$$

Whakaoti mō x

$$x=-11$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te \frac{1}{3} ki te x-1.

$$\frac{1}{3}x+\frac{1}{3}\left(-1\right)-1=\frac{1}{2}\left(x+1\right)$$

Whakareatia te \frac{1}{3} ki te -1, ka -\frac{1}{3}.

$$\frac{1}{3}x-\frac{1}{3}-1=\frac{1}{2}\left(x+1\right)$$

Me tahuri te 1 ki te hautau \frac{3}{3}.

$$\frac{1}{3}x-\frac{1}{3}-\frac{3}{3}=\frac{1}{2}\left(x+1\right)$$

Tā te mea he rite te tauraro o -\frac{1}{3} me \frac{3}{3}, me tango rāua mā te tango i ō raua taurunga.

$$\frac{1}{3}x+\frac{-1-3}{3}=\frac{1}{2}\left(x+1\right)$$

Tangohia te 3 i te -1, ka -4.

$$\frac{1}{3}x-\frac{4}{3}=\frac{1}{2}\left(x+1\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te \frac{1}{2} ki te x+1.

$$\frac{1}{3}x-\frac{4}{3}=\frac{1}{2}x+\frac{1}{2}$$

Tangohia te \frac{1}{2}x mai i ngā taha e rua.

$$\frac{1}{3}x-\frac{4}{3}-\frac{1}{2}x=\frac{1}{2}$$

Pahekotia te \frac{1}{3}x me -\frac{1}{2}x, ka -\frac{1}{6}x.

$$-\frac{1}{6}x-\frac{4}{3}=\frac{1}{2}$$

Me tāpiri te \frac{4}{3} ki ngā taha e rua.

$$-\frac{1}{6}x=\frac{1}{2}+\frac{4}{3}$$

Ko te maha noa iti rawa atu o 2 me 3 ko 6. Me tahuri \frac{1}{2} me \frac{4}{3} ki te hautau me te tautūnga 6.

$$-\frac{1}{6}x=\frac{3}{6}+\frac{8}{6}$$

Tā te mea he rite te tauraro o \frac{3}{6} me \frac{8}{6}, me tāpiri rāua mā te tāpiri i ō raua taurunga.

$$-\frac{1}{6}x=\frac{3+8}{6}$$

Tāpirihia te 3 ki te 8, ka 11.

$$-\frac{1}{6}x=\frac{11}{6}$$

Me whakarea ngā taha e rua ki te -6, te tau utu o -\frac{1}{6}.

$$x=\frac{11}{6}\left(-6\right)$$

Tuhia te \frac{11}{6}\left(-6\right) hei hautanga kotahi.

$$x=\frac{11\left(-6\right)}{6}$$

Whakareatia te 11 ki te -6, ka -66.

$$x=\frac{-66}{6}$$

Whakawehea te -66 ki te 6, kia riro ko -11.

$$x=-11$$