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\frac{1}{3}+x-\frac{3}{3}=0
Me tahuri te 1 ki te hautau \frac{3}{3}.
\frac{1-3}{3}+x=0
Tā te mea he rite te tauraro o \frac{1}{3} me \frac{3}{3}, me tango rāua mā te tango i ō raua taurunga.
-\frac{2}{3}+x=0
Tangohia te 3 i te 1, ka -2.
x=\frac{2}{3}
Me tāpiri te \frac{2}{3} ki ngā taha e rua. Ko te tau i tāpiria he kore ka hua koia tonu.