Whakaoti i te 1/3+4/1-(4/3*2/6)=frac{1}{4})+frac{18}{9}*frac{1}{2}

$$\frac { 1 } { 3 } + \frac { 4 } { 1 } - ( \frac { 4 } { 3 } \cdot \frac { 2 } { 6 } ) = \frac { 1 } { 4 } ) + \frac { 18 } { 9 } \cdot \frac { 1 } { 2 }$$

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Ka whakawehea he tau ki te tahi, hua ai ko ia anō.

$$\frac{1}{3}+4-\frac{4}{3}\times \frac{2}{6}=\frac{1}{4}$$

Me tahuri te 4 ki te hautau \frac{12}{3}.

$$\frac{1}{3}+\frac{12}{3}-\frac{4}{3}\times \frac{2}{6}=\frac{1}{4}$$

Tā te mea he rite te tauraro o \frac{1}{3} me \frac{12}{3}, me tāpiri rāua mā te tāpiri i ō raua taurunga.

$$\frac{1+12}{3}-\frac{4}{3}\times \frac{2}{6}=\frac{1}{4}$$

Tāpirihia te 1 ki te 12, ka 13.

$$\frac{13}{3}-\frac{4}{3}\times \frac{2}{6}=\frac{1}{4}$$

Whakahekea te hautanga \frac{2}{6} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 2.

$$\frac{13}{3}-\frac{4}{3}\times \frac{1}{3}=\frac{1}{4}$$

Me whakarea te \frac{4}{3} ki te \frac{1}{3} mā te whakarea taurunga ki te taurunga me te tauraro ki te tauraro.

$$\frac{13}{3}-\frac{4\times 1}{3\times 3}=\frac{1}{4}$$

Mahia ngā whakarea i roto i te hautanga \frac{4\times 1}{3\times 3}.

$$\frac{13}{3}-\frac{4}{9}=\frac{1}{4}$$

Ko te maha noa iti rawa atu o 3 me 9 ko 9. Me tahuri \frac{13}{3} me \frac{4}{9} ki te hautau me te tautūnga 9.

$$\frac{39}{9}-\frac{4}{9}=\frac{1}{4}$$

Tā te mea he rite te tauraro o \frac{39}{9} me \frac{4}{9}, me tango rāua mā te tango i ō raua taurunga.

$$\frac{39-4}{9}=\frac{1}{4}$$

Tangohia te 4 i te 39, ka 35.

$$\frac{35}{9}=\frac{1}{4}$$

Ko te maha noa iti rawa atu o 9 me 4 ko 36. Me tahuri \frac{35}{9} me \frac{1}{4} ki te hautau me te tautūnga 36.

$$\frac{140}{36}=\frac{9}{36}$$

Whakatauritea te \frac{140}{36} me te \frac{9}{36}.

$$\text{false}$$