Whakaoti i te 1/25(20-x)=4/25x-3/5

$$\frac { 1 } { 25 } ( 20 - x ) = \frac { 4 } { 25 } x - \frac { 3 } { 5 }$$

Whakaoti mō x

$$x=7$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te \frac{1}{25} ki te 20-x.

$$\frac{1}{25}\times 20+\frac{1}{25}\left(-1\right)x=\frac{4}{25}x-\frac{3}{5}$$

Whakareatia te \frac{1}{25} ki te 20, ka \frac{20}{25}.

$$\frac{20}{25}+\frac{1}{25}\left(-1\right)x=\frac{4}{25}x-\frac{3}{5}$$

Whakahekea te hautanga \frac{20}{25} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 5.

$$\frac{4}{5}+\frac{1}{25}\left(-1\right)x=\frac{4}{25}x-\frac{3}{5}$$

Whakareatia te \frac{1}{25} ki te -1, ka -\frac{1}{25}.

$$\frac{4}{5}-\frac{1}{25}x=\frac{4}{25}x-\frac{3}{5}$$

Tangohia te \frac{4}{25}x mai i ngā taha e rua.

$$\frac{4}{5}-\frac{1}{25}x-\frac{4}{25}x=-\frac{3}{5}$$

Pahekotia te -\frac{1}{25}x me -\frac{4}{25}x, ka -\frac{1}{5}x.

$$\frac{4}{5}-\frac{1}{5}x=-\frac{3}{5}$$

Tangohia te \frac{4}{5} mai i ngā taha e rua.

$$-\frac{1}{5}x=-\frac{3}{5}-\frac{4}{5}$$

Tā te mea he rite te tauraro o -\frac{3}{5} me \frac{4}{5}, me tango rāua mā te tango i ō raua taurunga.

$$-\frac{1}{5}x=\frac{-3-4}{5}$$

Tangohia te 4 i te -3, ka -7.

$$-\frac{1}{5}x=-\frac{7}{5}$$

Me whakarea ngā taha e rua ki te -5, te tau utu o -\frac{1}{5}.

$$x=-\frac{7}{5}\left(-5\right)$$

Tuhia te -\frac{7}{5}\left(-5\right) hei hautanga kotahi.

$$x=\frac{-7\left(-5\right)}{5}$$

Whakareatia te -7 ki te -5, ka 35.

$$x=\frac{35}{5}$$

Whakawehea te 35 ki te 5, kia riro ko 7.

$$x=7$$