Whakaoti i te 1/2x^2-x-3-1/2x^2+x-1

$$\frac { 1 } { 2 x ^ { 2 } - x - 3 } - \frac { 1 } { 2 x ^ { 2 } + x - 1 }$$

Aromātai

$$\frac{2}{\left(2x-3\right)\left(2x-1\right)\left(x+1\right)}$$

Ngā Hipanga Rongoā Poto

Tauwehea te 2x^{2}-x-3. Tauwehea te 2x^{2}+x-1.

$$\frac{1}{\left(2x-3\right)\left(x+1\right)}-\frac{1}{\left(2x-1\right)\left(x+1\right)}$$

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Ko te taurea pātahi iti rawa o \left(2x-3\right)\left(x+1\right) me \left(2x-1\right)\left(x+1\right) ko \left(2x-3\right)\left(2x-1\right)\left(x+1\right). Whakareatia \frac{1}{\left(2x-3\right)\left(x+1\right)} ki te \frac{2x-1}{2x-1}. Whakareatia \frac{1}{\left(2x-1\right)\left(x+1\right)} ki te \frac{2x-3}{2x-3}.

$$\frac{2x-1}{\left(2x-3\right)\left(2x-1\right)\left(x+1\right)}-\frac{2x-3}{\left(2x-3\right)\left(2x-1\right)\left(x+1\right)}$$

Tā te mea he rite te tauraro o \frac{2x-1}{\left(2x-3\right)\left(2x-1\right)\left(x+1\right)} me \frac{2x-3}{\left(2x-3\right)\left(2x-1\right)\left(x+1\right)}, me tango rāua mā te tango i ō raua taurunga.

$$\frac{2x-1-\left(2x-3\right)}{\left(2x-3\right)\left(2x-1\right)\left(x+1\right)}$$

Mahia ngā whakarea i roto o 2x-1-\left(2x-3\right).

$$\frac{2x-1-2x+3}{\left(2x-3\right)\left(2x-1\right)\left(x+1\right)}$$

Whakakotahitia ngā kupu rite i 2x-1-2x+3.

$$\frac{2}{\left(2x-3\right)\left(2x-1\right)\left(x+1\right)}$$

Whakarohaina te \left(2x-3\right)\left(2x-1\right)\left(x+1\right).

$$\frac{2}{4x^{3}-4x^{2}-5x+3}$$

Kimi Pārōnaki e ai ki x

$$-\frac{2\left(\left(6x-2\right)^{2}-19\right)}{3\left(\left(2x-3\right)\left(2x-1\right)\left(x+1\right)\right)^{2}}$$