Whakaoti i te 1/2-i+1-i/i(1+i)

$$\frac { 1 } { 2 - i } + \frac { 1 - i } { i ( 1 + i ) }$$

Aromātai

$$-\frac{3}{5}+\frac{1}{5}i=-0.6+0.2i$$

Ngā Upane Otinga

Me whakarea te taurunga me te tauraro o \frac{1}{2-i} ki te haumi hiato o te tauraro, 2+i.

$$\frac{1\left(2+i\right)}{\left(2-i\right)\left(2+i\right)}+\frac{1-i}{i\left(1+i\right)}$$

Ka taea te whakareanga te panoni ki te rerekētanga o ngā pūrua mā te ture: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

$$\frac{1\left(2+i\right)}{2^{2}-i^{2}}+\frac{1-i}{i\left(1+i\right)}$$

Hei tōna tikanga, ko te i^{2} ko -1. Tātaitia te tauraro.

$$\frac{1\left(2+i\right)}{5}+\frac{1-i}{i\left(1+i\right)}$$

Whakareatia te 1 ki te 2+i, ka 2+i.

$$\frac{2+i}{5}+\frac{1-i}{i\left(1+i\right)}$$

Whakawehea te 2+i ki te 5, kia riro ko \frac{2}{5}+\frac{1}{5}i.

$$\frac{2}{5}+\frac{1}{5}i+\frac{1-i}{i\left(1+i\right)}$$

Whakareatia i ki te 1+i.

$$\frac{2}{5}+\frac{1}{5}i+\frac{1-i}{i+i^{2}}$$

Hei tōna tikanga, ko te i^{2} ko -1.

$$\frac{2}{5}+\frac{1}{5}i+\frac{1-i}{i-1}$$

Whakaraupapatia anō ngā kīanga tau.

$$\frac{2}{5}+\frac{1}{5}i+\frac{1-i}{-1+i}$$

Whakawehea te 1-i ki te -1+i, kia riro ko -1.

$$\frac{2}{5}+\frac{1}{5}i-1$$

Tangohia te 1 i te \frac{2}{5}+\frac{1}{5}i mā te tango i ngā wāhi tūturu me ngā wāhi pohewa hāngai.

$$\frac{2}{5}-1+\frac{1}{5}i$$

Tangohia te 1 i te \frac{2}{5}, ka -\frac{3}{5}.

$$-\frac{3}{5}+\frac{1}{5}i$$

Wāhi Tūturu

$$-\frac{3}{5} = -0.6$$

Ngā Upane Otinga

Me whakarea te taurunga me te tauraro o \frac{1}{2-i} ki te haumi hiato o te tauraro, 2+i.

$$Re(\frac{1\left(2+i\right)}{\left(2-i\right)\left(2+i\right)}+\frac{1-i}{i\left(1+i\right)})$$

Ka taea te whakareanga te panoni ki te rerekētanga o ngā pūrua mā te ture: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

$$Re(\frac{1\left(2+i\right)}{2^{2}-i^{2}}+\frac{1-i}{i\left(1+i\right)})$$

Hei tōna tikanga, ko te i^{2} ko -1. Tātaitia te tauraro.

$$Re(\frac{1\left(2+i\right)}{5}+\frac{1-i}{i\left(1+i\right)})$$

Whakareatia te 1 ki te 2+i, ka 2+i.

$$Re(\frac{2+i}{5}+\frac{1-i}{i\left(1+i\right)})$$

Whakawehea te 2+i ki te 5, kia riro ko \frac{2}{5}+\frac{1}{5}i.

$$Re(\frac{2}{5}+\frac{1}{5}i+\frac{1-i}{i\left(1+i\right)})$$

Whakareatia i ki te 1+i.

$$Re(\frac{2}{5}+\frac{1}{5}i+\frac{1-i}{i+i^{2}})$$

Hei tōna tikanga, ko te i^{2} ko -1.

$$Re(\frac{2}{5}+\frac{1}{5}i+\frac{1-i}{i-1})$$

Whakaraupapatia anō ngā kīanga tau.

$$Re(\frac{2}{5}+\frac{1}{5}i+\frac{1-i}{-1+i})$$

Whakawehea te 1-i ki te -1+i, kia riro ko -1.

$$Re(\frac{2}{5}+\frac{1}{5}i-1)$$

Tangohia te 1 i te \frac{2}{5}+\frac{1}{5}i mā te tango i ngā wāhi tūturu me ngā wāhi pohewa hāngai.

$$Re(\frac{2}{5}-1+\frac{1}{5}i)$$

Tangohia te 1 i te \frac{2}{5}, ka -\frac{3}{5}.

$$Re(-\frac{3}{5}+\frac{1}{5}i)$$

Ko te wāhi tūturu o -\frac{3}{5}+\frac{1}{5}i ko -\frac{3}{5}.

$$-\frac{3}{5}$$