Whakaoti i te 1/2mv^2=1/2*(2.1*10^3)(2.9*10^3)^2

$$\frac { 1 } { 2 } m v ^ { 2 } = \frac { 1 } { 2 } \cdot ( 2.1 \times 10 ^ { 3 } ) ( 2.9 \times 10 ^ { 3 } ) ^ { 2 }$$

Whakaoti mō m

$$m=\frac{17661000000}{v^{2}}$$

$$v\neq 0$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Me whakakore te \frac{1}{2} ki ngā taha e rua.

$$mv^{2}=2.1\times 10^{3}\times \left(2.9\times 10^{3}\right)^{2}$$

Tātaihia te 10 mā te pū o 3, kia riro ko 1000.

$$mv^{2}=2.1\times 1000\times \left(2.9\times 10^{3}\right)^{2}$$

Whakareatia te 2.1 ki te 1000, ka 2100.

$$mv^{2}=2100\times \left(2.9\times 10^{3}\right)^{2}$$

Tātaihia te 10 mā te pū o 3, kia riro ko 1000.

$$mv^{2}=2100\times \left(2.9\times 1000\right)^{2}$$

Whakareatia te 2.9 ki te 1000, ka 2900.

$$mv^{2}=2100\times 2900^{2}$$

Tātaihia te 2900 mā te pū o 2, kia riro ko 8410000.

$$mv^{2}=2100\times 8410000$$

Whakareatia te 2100 ki te 8410000, ka 17661000000.

$$mv^{2}=17661000000$$

He hanga arowhānui tō te whārite.

$$v^{2}m=17661000000$$

Whakawehea ngā taha e rua ki te v^{2}.

$$\frac{v^{2}m}{v^{2}}=\frac{17661000000}{v^{2}}$$

Mā te whakawehe ki te v^{2} ka wetekia te whakareanga ki te v^{2}.

$$m=\frac{17661000000}{v^{2}}$$

Whakaoti mō v (complex solution)

$$v=-29000\sqrt{21}m^{-0.5}$$

$$v=29000\sqrt{21}m^{-0.5}\text{, }m\neq 0$$

Whakaoti mō v

$$v=29000\sqrt{\frac{21}{m}}$$

$$v=-29000\sqrt{\frac{21}{m}}\text{, }m>0$$