Whakaoti i te 1/2(x+3)=2x+6

$$\frac { 1 } { 2 } ( x + 3 ) = 2 x + 6$$

Whakaoti mō x

$$x=-3$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te \frac{1}{2} ki te x+3.

$$\frac{1}{2}x+\frac{1}{2}\times 3=2x+6$$

Whakareatia te \frac{1}{2} ki te 3, ka \frac{3}{2}.

$$\frac{1}{2}x+\frac{3}{2}=2x+6$$

Tangohia te 2x mai i ngā taha e rua.

$$\frac{1}{2}x+\frac{3}{2}-2x=6$$

Pahekotia te \frac{1}{2}x me -2x, ka -\frac{3}{2}x.

$$-\frac{3}{2}x+\frac{3}{2}=6$$

Tangohia te \frac{3}{2} mai i ngā taha e rua.

$$-\frac{3}{2}x=6-\frac{3}{2}$$

Me tahuri te 6 ki te hautau \frac{12}{2}.

$$-\frac{3}{2}x=\frac{12}{2}-\frac{3}{2}$$

Tā te mea he rite te tauraro o \frac{12}{2} me \frac{3}{2}, me tango rāua mā te tango i ō raua taurunga.

$$-\frac{3}{2}x=\frac{12-3}{2}$$

Tangohia te 3 i te 12, ka 9.

$$-\frac{3}{2}x=\frac{9}{2}$$

Me whakarea ngā taha e rua ki te -\frac{2}{3}, te tau utu o -\frac{3}{2}.

$$x=\frac{9}{2}\left(-\frac{2}{3}\right)$$

Me whakarea te \frac{9}{2} ki te -\frac{2}{3} mā te whakarea taurunga ki te taurunga me te tauraro ki te tauraro.

$$x=\frac{9\left(-2\right)}{2\times 3}$$

Mahia ngā whakarea i roto i te hautanga \frac{9\left(-2\right)}{2\times 3}.

$$x=\frac{-18}{6}$$

Whakawehea te -18 ki te 6, kia riro ko -3.

$$x=-3$$