Whakaoti i te 1/2(4y+2)-20<-1/3(9y-3)

$$\frac { 1 } { 2 } ( 4 y + 2 ) - 20 < - \frac { 1 } { 3 } ( 9 y - 3 )$$

Whakaoti mō y

$$y<4$$

Ngā Upane Otinga

Whakamahia te āhuatanga tohatoha hei whakarea te \frac{1}{2} ki te 4y+2.

$$\frac{1}{2}\times 4y+\frac{1}{2}\times 2-20<-\frac{1}{3}\left(9y-3\right)$$

Whakareatia te \frac{1}{2} ki te 4, ka \frac{4}{2}.

$$\frac{4}{2}y+\frac{1}{2}\times 2-20<-\frac{1}{3}\left(9y-3\right)$$

Whakawehea te 4 ki te 2, kia riro ko 2.

$$2y+\frac{1}{2}\times 2-20<-\frac{1}{3}\left(9y-3\right)$$

Me whakakore te 2 me te 2.

$$2y+1-20<-\frac{1}{3}\left(9y-3\right)$$

Tangohia te 20 i te 1, ka -19.

$$2y-19<-\frac{1}{3}\left(9y-3\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te -\frac{1}{3} ki te 9y-3.

$$2y-19<-\frac{1}{3}\times 9y-\frac{1}{3}\left(-3\right)$$

Tuhia te -\frac{1}{3}\times 9 hei hautanga kotahi.

$$2y-19<\frac{-9}{3}y-\frac{1}{3}\left(-3\right)$$

Whakawehea te -9 ki te 3, kia riro ko -3.

$$2y-19<-3y-\frac{1}{3}\left(-3\right)$$

Tuhia te -\frac{1}{3}\left(-3\right) hei hautanga kotahi.

$$2y-19<-3y+\frac{-\left(-3\right)}{3}$$

Whakareatia te -1 ki te -3, ka 3.

$$2y-19<-3y+\frac{3}{3}$$

Whakawehea te 3 ki te 3, kia riro ko 1.

$$2y-19<-3y+1$$

Me tāpiri te 3y ki ngā taha e rua.

$$2y-19+3y<1$$

Pahekotia te 2y me 3y, ka 5y.

$$5y-19<1$$

Me tāpiri te 19 ki ngā taha e rua.

$$5y<1+19$$

Tāpirihia te 1 ki te 19, ka 20.

$$5y<20$$

Whakawehea ngā taha e rua ki te 5. I te mea he tōrunga te 5, kāore e huri te ahunga koreōrite.

$$y<\frac{20}{5}$$

Whakawehea te 20 ki te 5, kia riro ko 4.

$$y<4$$