Whakaoti i te 1/2(4m+8)=1/3(3m-3)

$$\frac { 1 } { 2 } ( 4 m + 8 ) = \frac { 1 } { 3 } ( 3 m - 3 )$$

Whakaoti mō m

$$m=-5$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te \frac{1}{2} ki te 4m+8.

$$\frac{1}{2}\times 4m+\frac{1}{2}\times 8=\frac{1}{3}\left(3m-3\right)$$

Whakareatia te \frac{1}{2} ki te 4, ka \frac{4}{2}.

$$\frac{4}{2}m+\frac{1}{2}\times 8=\frac{1}{3}\left(3m-3\right)$$

Whakawehea te 4 ki te 2, kia riro ko 2.

$$2m+\frac{1}{2}\times 8=\frac{1}{3}\left(3m-3\right)$$

Whakareatia te \frac{1}{2} ki te 8, ka \frac{8}{2}.

$$2m+\frac{8}{2}=\frac{1}{3}\left(3m-3\right)$$

Whakawehea te 8 ki te 2, kia riro ko 4.

$$2m+4=\frac{1}{3}\left(3m-3\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te \frac{1}{3} ki te 3m-3.

$$2m+4=\frac{1}{3}\times 3m+\frac{1}{3}\left(-3\right)$$

Me whakakore te 3 me te 3.

$$2m+4=m+\frac{1}{3}\left(-3\right)$$

Whakareatia te \frac{1}{3} ki te -3, ka \frac{-3}{3}.

$$2m+4=m+\frac{-3}{3}$$

Whakawehea te -3 ki te 3, kia riro ko -1.

$$2m+4=m-1$$

Tangohia te m mai i ngā taha e rua.

$$2m+4-m=-1$$

Pahekotia te 2m me -m, ka m.

$$m+4=-1$$

Tangohia te 4 mai i ngā taha e rua.

$$m=-1-4$$

Tangohia te 4 i te -1, ka -5.

$$m=-5$$