Whakaoti i te 1/2*(x+1)-4/3*1/6=2

$$\frac { 1 } { 2 } \cdot ( x + 1 ) - \frac { 4 } { 3 } \cdot \frac { 1 } { 6 } = 2$$

Whakaoti mō x

$$x = \frac{31}{9} = 3\frac{4}{9} \approx 3.444444444$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te \frac{1}{2} ki te x+1.

$$\frac{1}{2}x+\frac{1}{2}-\frac{4}{3}\times \frac{1}{6}=2$$

Me whakarea te \frac{4}{3} ki te \frac{1}{6} mā te whakarea taurunga ki te taurunga me te tauraro ki te tauraro.

$$\frac{1}{2}x+\frac{1}{2}-\frac{4\times 1}{3\times 6}=2$$

Mahia ngā whakarea i roto i te hautanga \frac{4\times 1}{3\times 6}.

$$\frac{1}{2}x+\frac{1}{2}-\frac{4}{18}=2$$

Whakahekea te hautanga \frac{4}{18} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 2.

$$\frac{1}{2}x+\frac{1}{2}-\frac{2}{9}=2$$

Ko te maha noa iti rawa atu o 2 me 9 ko 18. Me tahuri \frac{1}{2} me \frac{2}{9} ki te hautau me te tautūnga 18.

$$\frac{1}{2}x+\frac{9}{18}-\frac{4}{18}=2$$

Tā te mea he rite te tauraro o \frac{9}{18} me \frac{4}{18}, me tango rāua mā te tango i ō raua taurunga.

$$\frac{1}{2}x+\frac{9-4}{18}=2$$

Tangohia te 4 i te 9, ka 5.

$$\frac{1}{2}x+\frac{5}{18}=2$$

Tangohia te \frac{5}{18} mai i ngā taha e rua.

$$\frac{1}{2}x=2-\frac{5}{18}$$

Me tahuri te 2 ki te hautau \frac{36}{18}.

$$\frac{1}{2}x=\frac{36}{18}-\frac{5}{18}$$

Tā te mea he rite te tauraro o \frac{36}{18} me \frac{5}{18}, me tango rāua mā te tango i ō raua taurunga.

$$\frac{1}{2}x=\frac{36-5}{18}$$

Tangohia te 5 i te 36, ka 31.

$$\frac{1}{2}x=\frac{31}{18}$$

Me whakarea ngā taha e rua ki te 2, te tau utu o \frac{1}{2}.

$$x=\frac{31}{18}\times 2$$

Tuhia te \frac{31}{18}\times 2 hei hautanga kotahi.

$$x=\frac{31\times 2}{18}$$

Whakareatia te 31 ki te 2, ka 62.

$$x=\frac{62}{18}$$

Whakahekea te hautanga \frac{62}{18} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 2.

$$x=\frac{31}{9}$$