Whakaoti i te 1/2=-4/3v-3/5

$$\frac { 1 } { 2 } = - \frac { 4 } { 3 } v - \frac { 3 } { 5 }$$

Whakaoti mō v

$$v=-\frac{33}{40}=-0.825$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$-\frac{4}{3}v-\frac{3}{5}=\frac{1}{2}$$

Me tāpiri te \frac{3}{5} ki ngā taha e rua.

$$-\frac{4}{3}v=\frac{1}{2}+\frac{3}{5}$$

Ko te maha noa iti rawa atu o 2 me 5 ko 10. Me tahuri \frac{1}{2} me \frac{3}{5} ki te hautau me te tautūnga 10.

$$-\frac{4}{3}v=\frac{5}{10}+\frac{6}{10}$$

Tā te mea he rite te tauraro o \frac{5}{10} me \frac{6}{10}, me tāpiri rāua mā te tāpiri i ō raua taurunga.

$$-\frac{4}{3}v=\frac{5+6}{10}$$

Tāpirihia te 5 ki te 6, ka 11.

$$-\frac{4}{3}v=\frac{11}{10}$$

Me whakarea ngā taha e rua ki te -\frac{3}{4}, te tau utu o -\frac{4}{3}.

$$v=\frac{11}{10}\left(-\frac{3}{4}\right)$$

Me whakarea te \frac{11}{10} ki te -\frac{3}{4} mā te whakarea taurunga ki te taurunga me te tauraro ki te tauraro.

$$v=\frac{11\left(-3\right)}{10\times 4}$$

Mahia ngā whakarea i roto i te hautanga \frac{11\left(-3\right)}{10\times 4}.

$$v=\frac{-33}{40}$$

Ka taea te hautanga \frac{-33}{40} te tuhi anō ko -\frac{33}{40} mā te tango i te tohu tōraro.

$$v=-\frac{33}{40}$$