Whakaoti i te 1/2+3i

$$\frac { 1 } { 2 + 3 i }$$

Aromātai

$$\frac{2}{13}-\frac{3}{13}i\approx 0.153846154-0.230769231i$$

Ngā Upane Otinga

Whakareatia te taurunga me te tauraro ki te haumi hiato o te tauraro, 2-3i.

$$\frac{1\left(2-3i\right)}{\left(2+3i\right)\left(2-3i\right)}$$

Ka taea te whakareanga te panoni ki te rerekētanga o ngā pūrua mā te ture: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

$$\frac{1\left(2-3i\right)}{2^{2}-3^{2}i^{2}}$$

Hei tōna tikanga, ko te i^{2} ko -1. Tātaitia te tauraro.

$$\frac{1\left(2-3i\right)}{13}$$

Whakareatia te 1 ki te 2-3i, ka 2-3i.

$$\frac{2-3i}{13}$$

Whakawehea te 2-3i ki te 13, kia riro ko \frac{2}{13}-\frac{3}{13}i.

$$\frac{2}{13}-\frac{3}{13}i$$

Wāhi Tūturu

$$\frac{2}{13} = 0.15384615384615385$$

Ngā Upane Otinga

Me whakarea te taurunga me te tauraro o \frac{1}{2+3i} ki te haumi hiato o te tauraro, 2-3i.

$$Re(\frac{1\left(2-3i\right)}{\left(2+3i\right)\left(2-3i\right)})$$

Ka taea te whakareanga te panoni ki te rerekētanga o ngā pūrua mā te ture: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

$$Re(\frac{1\left(2-3i\right)}{2^{2}-3^{2}i^{2}})$$

Hei tōna tikanga, ko te i^{2} ko -1. Tātaitia te tauraro.

$$Re(\frac{1\left(2-3i\right)}{13})$$

Whakareatia te 1 ki te 2-3i, ka 2-3i.

$$Re(\frac{2-3i}{13})$$

Whakawehea te 2-3i ki te 13, kia riro ko \frac{2}{13}-\frac{3}{13}i.

$$Re(\frac{2}{13}-\frac{3}{13}i)$$

Ko te wāhi tūturu o \frac{2}{13}-\frac{3}{13}i ko \frac{2}{13}.

$$\frac{2}{13}$$