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Aromātai (complex solution)
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Tohaina

\frac{1}{-5i\sqrt{3}}
Tauwehea te -75=\left(5i\right)^{2}\times 3. Tuhia anō te pūtake rua o te hua \sqrt{\left(5i\right)^{2}\times 3} hei hua o ngā pūtake rua \sqrt{\left(5i\right)^{2}}\sqrt{3}. Tuhia te pūtakerua o te \left(5i\right)^{2}.
\frac{\sqrt{3}}{-5i\left(\sqrt{3}\right)^{2}}
Whakangāwaritia te tauraro o \frac{1}{-5i\sqrt{3}} mā te whakarea i te taurunga me te tauraro ki te \sqrt{3}.
\frac{\sqrt{3}}{-5i\times 3}
Ko te pūrua o \sqrt{3} ko 3.
\frac{\sqrt{3}}{-15i}
Whakareatia te -5i ki te 3, ka -15i.