Whakaoti i te 1/(1-i)*5=

$$\frac { 1 } { ( 1 - i ) \cdot 5 } =$$

Aromātai

$$\frac{1}{10}+\frac{1}{10}i=0.1+0.1i$$

Ngā Upane Otinga

Whakareatia 1-i ki te 5.

$$\frac{1}{1\times 5-i\times 5}$$

Mahia ngā whakarea i roto o 1\times 5-i\times 5.

$$\frac{1}{5-5i}$$

Whakareatia te taurunga me te tauraro ki te haumi hiato o te tauraro, 5+5i.

$$\frac{1\left(5+5i\right)}{\left(5-5i\right)\left(5+5i\right)}$$

Ka taea te whakareanga te panoni ki te rerekētanga o ngā pūrua mā te ture: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

$$\frac{1\left(5+5i\right)}{5^{2}-5^{2}i^{2}}$$

Hei tōna tikanga, ko te i^{2} ko -1. Tātaitia te tauraro.

$$\frac{1\left(5+5i\right)}{50}$$

Whakareatia te 1 ki te 5+5i, ka 5+5i.

$$\frac{5+5i}{50}$$

Whakawehea te 5+5i ki te 50, kia riro ko \frac{1}{10}+\frac{1}{10}i.

$$\frac{1}{10}+\frac{1}{10}i$$

Wāhi Tūturu

$$\frac{1}{10} = 0.1$$

Ngā Upane Otinga

Whakareatia 1-i ki te 5.

$$Re(\frac{1}{1\times 5-i\times 5})$$

Mahia ngā whakarea i roto o 1\times 5-i\times 5.

$$Re(\frac{1}{5-5i})$$

Me whakarea te taurunga me te tauraro o \frac{1}{5-5i} ki te haumi hiato o te tauraro, 5+5i.

$$Re(\frac{1\left(5+5i\right)}{\left(5-5i\right)\left(5+5i\right)})$$

Ka taea te whakareanga te panoni ki te rerekētanga o ngā pūrua mā te ture: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

$$Re(\frac{1\left(5+5i\right)}{5^{2}-5^{2}i^{2}})$$

Hei tōna tikanga, ko te i^{2} ko -1. Tātaitia te tauraro.

$$Re(\frac{1\left(5+5i\right)}{50})$$

Whakareatia te 1 ki te 5+5i, ka 5+5i.

$$Re(\frac{5+5i}{50})$$

Whakawehea te 5+5i ki te 50, kia riro ko \frac{1}{10}+\frac{1}{10}i.

$$Re(\frac{1}{10}+\frac{1}{10}i)$$

Ko te wāhi tūturu o \frac{1}{10}+\frac{1}{10}i ko \frac{1}{10}.

$$\frac{1}{10}$$