Whakaoti i te 1/sqrt{3}[frac{x^{2}}{2}]_{0}^sqrt{3}*(frac{xsqrt{4-x^2}}{2}+4/2sin^-1x/2]_{sqrt{3}}^2

$$\frac { 1 } { \sqrt { 3 } } [ \frac { x ^ { 2 } } { 2 } ] _ { 0 } ^ { \sqrt { 3 } } \cdot ( \frac { x \sqrt { 4 - x ^ { 2 } } } { 2 } + \frac { 4 } { 2 } \sin ^ { - 1 } \frac { x } { 2 } ] _ { \sqrt { 3 } } ^ { 2 }$$

Aromātai

$$\frac{\sqrt{3}x^{2}}{6}$$

Ngā Upane Otinga

Whakangāwaritia te tauraro o \frac{1}{\sqrt{3}} mā te whakarea i te taurunga me te tauraro ki te \sqrt{3}.

$$\frac{\sqrt{3}}{\left(\sqrt{3}\right)^{2}}\times \frac{x^{2}}{2}$$

Ko te pūrua o \sqrt{3} ko 3.

$$\frac{\sqrt{3}}{3}\times \frac{x^{2}}{2}$$

Me whakarea te \frac{\sqrt{3}}{3} ki te \frac{x^{2}}{2} mā te whakarea taurunga ki te taurunga me te tauraro ki te tauraro.

$$\frac{\sqrt{3}x^{2}}{3\times 2}$$

Whakareatia te 3 ki te 2, ka 6.

$$\frac{\sqrt{3}x^{2}}{6}$$

Kimi Pārōnaki e ai ki x

$$\frac{\sqrt{3}x}{3}$$