Whakaoti i te 1/sqrt{(0)+5}-(4(0)+2)

$$\frac { 1 } { \sqrt { ( 0 ) + 5 } } - ( 4 ( 0 ) + 2 )$$

Aromātai

$$\frac{\sqrt{5}}{5}-2\approx -1.552786405$$

Ngā Hipanga Rongoā Poto

Tāpirihia te 0 ki te 5, ka 5.

$$\frac{1}{\sqrt{5}}-\left(4\times 0+2\right)$$

Whakangāwaritia te tauraro o \frac{1}{\sqrt{5}} mā te whakarea i te taurunga me te tauraro ki te \sqrt{5}.

$$\frac{\sqrt{5}}{\left(\sqrt{5}\right)^{2}}-\left(4\times 0+2\right)$$

Ko te pūrua o \sqrt{5} ko 5.

$$\frac{\sqrt{5}}{5}-\left(4\times 0+2\right)$$

Whakareatia te 4 ki te 0, ka 0.

$$\frac{\sqrt{5}}{5}-\left(0+2\right)$$

Tāpirihia te 0 ki te 2, ka 2.

$$\frac{\sqrt{5}}{5}-2$$

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Whakareatia 2 ki te \frac{5}{5}.

$$\frac{\sqrt{5}}{5}-\frac{2\times 5}{5}$$

Tā te mea he rite te tauraro o \frac{\sqrt{5}}{5} me \frac{2\times 5}{5}, me tango rāua mā te tango i ō raua taurunga.

$$\frac{\sqrt{5}-2\times 5}{5}$$

Mahia ngā whakarea i roto o \sqrt{5}-2\times 5.

$$\frac{\sqrt{5}-10}{5}$$