Whakaoti i te 1+i/3-2i

$$\frac { 1 + i } { 3 - 2 i }$$

Aromātai

$$\frac{1}{13}+\frac{5}{13}i\approx 0.076923077+0.384615385i$$

Ngā Upane Otinga

Whakareatia te taurunga me te tauraro ki te haumi hiato o te tauraro, 3+2i.

$$\frac{\left(1+i\right)\left(3+2i\right)}{\left(3-2i\right)\left(3+2i\right)}$$

Ka taea te whakareanga te panoni ki te rerekētanga o ngā pūrua mā te ture: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

$$\frac{\left(1+i\right)\left(3+2i\right)}{3^{2}-2^{2}i^{2}}$$

Hei tōna tikanga, ko te i^{2} ko -1. Tātaitia te tauraro.

$$\frac{\left(1+i\right)\left(3+2i\right)}{13}$$

Me whakarea ngā tau matatini 1+i me 3+2i pēnā i te whakarea huarua.

$$\frac{1\times 3+1\times \left(2i\right)+3i+2i^{2}}{13}$$

Hei tōna tikanga, ko te i^{2} ko -1.

$$\frac{1\times 3+1\times \left(2i\right)+3i+2\left(-1\right)}{13}$$

Mahia ngā whakarea i roto o 1\times 3+1\times \left(2i\right)+3i+2\left(-1\right).

$$\frac{3+2i+3i-2}{13}$$

Whakakotahitia ngā wāhi tūturu me ngā wāhi pōhewa ki 3+2i+3i-2.

$$\frac{3-2+\left(2+3\right)i}{13}$$

Mahia ngā tāpiri i roto o 3-2+\left(2+3\right)i.

$$\frac{1+5i}{13}$$

Whakawehea te 1+5i ki te 13, kia riro ko \frac{1}{13}+\frac{5}{13}i.

$$\frac{1}{13}+\frac{5}{13}i$$

Wāhi Tūturu

$$\frac{1}{13} = 0.07692307692307693$$

Ngā Upane Otinga

Me whakarea te taurunga me te tauraro o \frac{1+i}{3-2i} ki te haumi hiato o te tauraro, 3+2i.

$$Re(\frac{\left(1+i\right)\left(3+2i\right)}{\left(3-2i\right)\left(3+2i\right)})$$

Ka taea te whakareanga te panoni ki te rerekētanga o ngā pūrua mā te ture: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

$$Re(\frac{\left(1+i\right)\left(3+2i\right)}{3^{2}-2^{2}i^{2}})$$

Hei tōna tikanga, ko te i^{2} ko -1. Tātaitia te tauraro.

$$Re(\frac{\left(1+i\right)\left(3+2i\right)}{13})$$

Me whakarea ngā tau matatini 1+i me 3+2i pēnā i te whakarea huarua.

$$Re(\frac{1\times 3+1\times \left(2i\right)+3i+2i^{2}}{13})$$

Hei tōna tikanga, ko te i^{2} ko -1.

$$Re(\frac{1\times 3+1\times \left(2i\right)+3i+2\left(-1\right)}{13})$$

Mahia ngā whakarea i roto o 1\times 3+1\times \left(2i\right)+3i+2\left(-1\right).

$$Re(\frac{3+2i+3i-2}{13})$$

Whakakotahitia ngā wāhi tūturu me ngā wāhi pōhewa ki 3+2i+3i-2.

$$Re(\frac{3-2+\left(2+3\right)i}{13})$$

Mahia ngā tāpiri i roto o 3-2+\left(2+3\right)i.

$$Re(\frac{1+5i}{13})$$

Whakawehea te 1+5i ki te 13, kia riro ko \frac{1}{13}+\frac{5}{13}i.

$$Re(\frac{1}{13}+\frac{5}{13}i)$$

Ko te wāhi tūturu o \frac{1}{13}+\frac{5}{13}i ko \frac{1}{13}.

$$\frac{1}{13}$$