Whakaoti i te 1+i/1-i

$$\frac { 1 + i } { 1 - i }$$

Aromātai

$$i$$

Ngā Upane Otinga

Whakareatia te taurunga me te tauraro ki te haumi hiato o te tauraro, 1+i.

$$\frac{\left(1+i\right)\left(1+i\right)}{\left(1-i\right)\left(1+i\right)}$$

Ka taea te whakareanga te panoni ki te rerekētanga o ngā pūrua mā te ture: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

$$\frac{\left(1+i\right)\left(1+i\right)}{1^{2}-i^{2}}$$

Hei tōna tikanga, ko te i^{2} ko -1. Tātaitia te tauraro.

$$\frac{\left(1+i\right)\left(1+i\right)}{2}$$

Me whakarea ngā tau matatini 1+i me 1+i pēnā i te whakarea huarua.

$$\frac{1\times 1+i+i+i^{2}}{2}$$

Hei tōna tikanga, ko te i^{2} ko -1.

$$\frac{1\times 1+i+i-1}{2}$$

Mahia ngā whakarea i roto o 1\times 1+i+i-1.

$$\frac{1+i+i-1}{2}$$

Whakakotahitia ngā wāhi tūturu me ngā wāhi pōhewa ki 1+i+i-1.

$$\frac{1-1+\left(1+1\right)i}{2}$$

Mahia ngā tāpiri i roto o 1-1+\left(1+1\right)i.

$$\frac{2i}{2}$$

Whakawehea te 2i ki te 2, kia riro ko i.

$$i$$

Wāhi Tūturu

$$0$$

Ngā Upane Otinga

Me whakarea te taurunga me te tauraro o \frac{1+i}{1-i} ki te haumi hiato o te tauraro, 1+i.

$$Re(\frac{\left(1+i\right)\left(1+i\right)}{\left(1-i\right)\left(1+i\right)})$$

Ka taea te whakareanga te panoni ki te rerekētanga o ngā pūrua mā te ture: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

$$Re(\frac{\left(1+i\right)\left(1+i\right)}{1^{2}-i^{2}})$$

Hei tōna tikanga, ko te i^{2} ko -1. Tātaitia te tauraro.

$$Re(\frac{\left(1+i\right)\left(1+i\right)}{2})$$

Me whakarea ngā tau matatini 1+i me 1+i pēnā i te whakarea huarua.

$$Re(\frac{1\times 1+i+i+i^{2}}{2})$$

Hei tōna tikanga, ko te i^{2} ko -1.

$$Re(\frac{1\times 1+i+i-1}{2})$$

Mahia ngā whakarea i roto o 1\times 1+i+i-1.

$$Re(\frac{1+i+i-1}{2})$$

Whakakotahitia ngā wāhi tūturu me ngā wāhi pōhewa ki 1+i+i-1.

$$Re(\frac{1-1+\left(1+1\right)i}{2})$$

Mahia ngā tāpiri i roto o 1-1+\left(1+1\right)i.

$$Re(\frac{2i}{2})$$

Whakawehea te 2i ki te 2, kia riro ko i.

$$Re(i)$$

Ko te wāhi tūturu o i ko 0.

$$0$$