Whakaoti i te 1+2i/1-2i

$$\frac { 1 + 2 i } { 1 - 2 i }$$

Aromātai

$$-\frac{3}{5}+\frac{4}{5}i=-0.6+0.8i$$

Ngā Upane Otinga

Whakareatia te taurunga me te tauraro ki te haumi hiato o te tauraro, 1+2i.

$$\frac{\left(1+2i\right)\left(1+2i\right)}{\left(1-2i\right)\left(1+2i\right)}$$

Ka taea te whakareanga te panoni ki te rerekētanga o ngā pūrua mā te ture: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

$$\frac{\left(1+2i\right)\left(1+2i\right)}{1^{2}-2^{2}i^{2}}$$

Hei tōna tikanga, ko te i^{2} ko -1. Tātaitia te tauraro.

$$\frac{\left(1+2i\right)\left(1+2i\right)}{5}$$

Me whakarea ngā tau matatini 1+2i me 1+2i pēnā i te whakarea huarua.

$$\frac{1\times 1+1\times \left(2i\right)+2i\times 1+2\times 2i^{2}}{5}$$

Hei tōna tikanga, ko te i^{2} ko -1.

$$\frac{1\times 1+1\times \left(2i\right)+2i\times 1+2\times 2\left(-1\right)}{5}$$

Mahia ngā whakarea i roto o 1\times 1+1\times \left(2i\right)+2i\times 1+2\times 2\left(-1\right).

$$\frac{1+2i+2i-4}{5}$$

Whakakotahitia ngā wāhi tūturu me ngā wāhi pōhewa ki 1+2i+2i-4.

$$\frac{1-4+\left(2+2\right)i}{5}$$

Mahia ngā tāpiri i roto o 1-4+\left(2+2\right)i.

$$\frac{-3+4i}{5}$$

Whakawehea te -3+4i ki te 5, kia riro ko -\frac{3}{5}+\frac{4}{5}i.

$$-\frac{3}{5}+\frac{4}{5}i$$

Wāhi Tūturu

$$-\frac{3}{5} = -0.6$$

Ngā Upane Otinga

Me whakarea te taurunga me te tauraro o \frac{1+2i}{1-2i} ki te haumi hiato o te tauraro, 1+2i.

$$Re(\frac{\left(1+2i\right)\left(1+2i\right)}{\left(1-2i\right)\left(1+2i\right)})$$

Ka taea te whakareanga te panoni ki te rerekētanga o ngā pūrua mā te ture: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

$$Re(\frac{\left(1+2i\right)\left(1+2i\right)}{1^{2}-2^{2}i^{2}})$$

Hei tōna tikanga, ko te i^{2} ko -1. Tātaitia te tauraro.

$$Re(\frac{\left(1+2i\right)\left(1+2i\right)}{5})$$

Me whakarea ngā tau matatini 1+2i me 1+2i pēnā i te whakarea huarua.

$$Re(\frac{1\times 1+1\times \left(2i\right)+2i\times 1+2\times 2i^{2}}{5})$$

Hei tōna tikanga, ko te i^{2} ko -1.

$$Re(\frac{1\times 1+1\times \left(2i\right)+2i\times 1+2\times 2\left(-1\right)}{5})$$

Mahia ngā whakarea i roto o 1\times 1+1\times \left(2i\right)+2i\times 1+2\times 2\left(-1\right).

$$Re(\frac{1+2i+2i-4}{5})$$

Whakakotahitia ngā wāhi tūturu me ngā wāhi pōhewa ki 1+2i+2i-4.

$$Re(\frac{1-4+\left(2+2\right)i}{5})$$

Mahia ngā tāpiri i roto o 1-4+\left(2+2\right)i.

$$Re(\frac{-3+4i}{5})$$

Whakawehea te -3+4i ki te 5, kia riro ko -\frac{3}{5}+\frac{4}{5}i.

$$Re(-\frac{3}{5}+\frac{4}{5}i)$$

Ko te wāhi tūturu o -\frac{3}{5}+\frac{4}{5}i ko -\frac{3}{5}.

$$-\frac{3}{5}$$