Whakaoti i te 1+1/2-i

$$\frac { 1 + 1 } { 2 - i }$$

Aromātai

$$\frac{4}{5}+\frac{2}{5}i=0.8+0.4i$$

Ngā Upane Otinga

Tāpirihia te 1 ki te 1, ka 2.

$$\frac{2}{2-i}$$

Whakareatia te taurunga me te tauraro ki te haumi hiato o te tauraro, 2+i.

$$\frac{2\left(2+i\right)}{\left(2-i\right)\left(2+i\right)}$$

Ka taea te whakareanga te panoni ki te rerekētanga o ngā pūrua mā te ture: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

$$\frac{2\left(2+i\right)}{2^{2}-i^{2}}$$

Hei tōna tikanga, ko te i^{2} ko -1. Tātaitia te tauraro.

$$\frac{2\left(2+i\right)}{5}$$

Whakareatia 2 ki te 2+i.

$$\frac{2\times 2+2i}{5}$$

Mahia ngā whakarea i roto o 2\times 2+2i.

$$\frac{4+2i}{5}$$

Whakawehea te 4+2i ki te 5, kia riro ko \frac{4}{5}+\frac{2}{5}i.

$$\frac{4}{5}+\frac{2}{5}i$$

Wāhi Tūturu

$$\frac{4}{5} = 0.8$$

Ngā Upane Otinga

Tāpirihia te 1 ki te 1, ka 2.

$$Re(\frac{2}{2-i})$$

Me whakarea te taurunga me te tauraro o \frac{2}{2-i} ki te haumi hiato o te tauraro, 2+i.

$$Re(\frac{2\left(2+i\right)}{\left(2-i\right)\left(2+i\right)})$$

Ka taea te whakareanga te panoni ki te rerekētanga o ngā pūrua mā te ture: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

$$Re(\frac{2\left(2+i\right)}{2^{2}-i^{2}})$$

Hei tōna tikanga, ko te i^{2} ko -1. Tātaitia te tauraro.

$$Re(\frac{2\left(2+i\right)}{5})$$

Whakareatia 2 ki te 2+i.

$$Re(\frac{2\times 2+2i}{5})$$

Mahia ngā whakarea i roto o 2\times 2+2i.

$$Re(\frac{4+2i}{5})$$

Whakawehea te 4+2i ki te 5, kia riro ko \frac{4}{5}+\frac{2}{5}i.

$$Re(\frac{4}{5}+\frac{2}{5}i)$$

Ko te wāhi tūturu o \frac{4}{5}+\frac{2}{5}i ko \frac{4}{5}.

$$\frac{4}{5}$$