Whakaoti i te frac{01^{-3}*5^{-2}}{(5/64*04^{3})^-2}*((1/5)^-2*025^2)^-3

Aromātai

Ngā Upane Otinga

Tauwehe

Pātaitai

Arithmetic

5 raruraru e ōrite ana ki:

Ngā Raru Ōrite mai i te Rapu Tukutuku

https://socratic.org/questions/how-do-you-find-the-nth-partial-sum-determine-whether-the-series-converges-and-f-9

https://math.stackexchange.com/questions/2949626/show-a-vector-identity-including-derivative-a-cdot-frac-partial-f-partial-q

https://math.stackexchange.com/questions/2947937/find-ex2-given-the-probability-mass-function

Tohaina

Kua tāruatia ki te papatopenga

\frac{0\times 1\times 5^{-2}}{\left(\frac{5}{64}\times 0\times 4^{3}\right)^{-2}}\times \left(\left(\frac{1}{5}\right)^{-2}\times 0\times 25^{2}\right)^{-3}

Tātaihia te 1 mā te pū o -3, kia riro ko 1.

\frac{0\times 5^{-2}}{\left(\frac{5}{64}\times 0\times 4^{3}\right)^{-2}}\times \left(\left(\frac{1}{5}\right)^{-2}\times 0\times 25^{2}\right)^{-3}

Whakareatia te 0 ki te 1, ka 0.

\frac{0\times \frac{1}{25}}{\left(\frac{5}{64}\times 0\times 4^{3}\right)^{-2}}\times \left(\left(\frac{1}{5}\right)^{-2}\times 0\times 25^{2}\right)^{-3}

Tātaihia te 5 mā te pū o -2, kia riro ko \frac{1}{25}.

\frac{0}{\left(\frac{5}{64}\times 0\times 4^{3}\right)^{-2}}\times \left(\left(\frac{1}{5}\right)^{-2}\times 0\times 25^{2}\right)^{-3}

Whakareatia te 0 ki te \frac{1}{25}, ka 0.

\frac{0}{\left(0\times 4^{3}\right)^{-2}}\times \left(\left(\frac{1}{5}\right)^{-2}\times 0\times 25^{2}\right)^{-3}

Whakareatia te \frac{5}{64} ki te 0, ka 0.

\frac{0}{\left(0\times 64\right)^{-2}}\times \left(\left(\frac{1}{5}\right)^{-2}\times 0\times 25^{2}\right)^{-3}

Tātaihia te 4 mā te pū o 3, kia riro ko 64.

\frac{0}{0^{-2}}\times \left(\left(\frac{1}{5}\right)^{-2}\times 0\times 25^{2}\right)^{-3}

Whakareatia te 0 ki te 64, ka 0.

\frac{0}{0^{-2}}\times \left(25\times 0\times 25^{2}\right)^{-3}

Tātaihia te \frac{1}{5} mā te pū o -2, kia riro ko 25.

\frac{0}{0^{-2}}\times \left(0\times 25^{2}\right)^{-3}