Whakaoti i te 0.4y+0.9/0.5-0.3+0.2y/0.3=1

$$\frac { 0.4 y + 0.9 } { 0.5 } - \frac { 0.3 + 0.2 y } { 0.3 } = 1$$

Whakaoti mō y

$$y=1.5$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakawehea ia wā o 0.4y+0.9 ki te 0.5, kia riro ko \frac{0.4y}{0.5}+\frac{0.9}{0.5}.

$$\frac{0.4y}{0.5}+\frac{0.9}{0.5}-\frac{0.3+0.2y}{0.3}=1$$

Whakawehea te 0.4y ki te 0.5, kia riro ko 0.8y.

$$0.8y+\frac{0.9}{0.5}-\frac{0.3+0.2y}{0.3}=1$$

Whakarohaina te \frac{0.9}{0.5} mā te whakarea i te taurunga me te tauraro ki te 10.

$$0.8y+\frac{9}{5}-\frac{0.3+0.2y}{0.3}=1$$

Whakawehea ia wā o 0.3+0.2y ki te 0.3, kia riro ko \frac{0.3}{0.3}+\frac{0.2y}{0.3}.

$$0.8y+\frac{9}{5}-\left(\frac{0.3}{0.3}+\frac{0.2y}{0.3}\right)=1$$

Whakawehea te 0.3 ki te 0.3, kia riro ko 1.

$$0.8y+\frac{9}{5}-\left(1+\frac{0.2y}{0.3}\right)=1$$

Whakawehea te 0.2y ki te 0.3, kia riro ko \frac{2}{3}y.

$$0.8y+\frac{9}{5}-\left(1+\frac{2}{3}y\right)=1$$

Hei kimi i te tauaro o 1+\frac{2}{3}y, kimihia te tauaro o ia taurangi.

$$0.8y+\frac{9}{5}-1-\frac{2}{3}y=1$$

Me tahuri te 1 ki te hautau \frac{5}{5}.

$$0.8y+\frac{9}{5}-\frac{5}{5}-\frac{2}{3}y=1$$

Tā te mea he rite te tauraro o \frac{9}{5} me \frac{5}{5}, me tango rāua mā te tango i ō raua taurunga.

$$0.8y+\frac{9-5}{5}-\frac{2}{3}y=1$$

Tangohia te 5 i te 9, ka 4.

$$0.8y+\frac{4}{5}-\frac{2}{3}y=1$$

Pahekotia te 0.8y me -\frac{2}{3}y, ka \frac{2}{15}y.

$$\frac{2}{15}y+\frac{4}{5}=1$$

Tangohia te \frac{4}{5} mai i ngā taha e rua.

$$\frac{2}{15}y=1-\frac{4}{5}$$

Me tahuri te 1 ki te hautau \frac{5}{5}.

$$\frac{2}{15}y=\frac{5}{5}-\frac{4}{5}$$

Tā te mea he rite te tauraro o \frac{5}{5} me \frac{4}{5}, me tango rāua mā te tango i ō raua taurunga.

$$\frac{2}{15}y=\frac{5-4}{5}$$

Tangohia te 4 i te 5, ka 1.

$$\frac{2}{15}y=\frac{1}{5}$$

Whakawehea ngā taha e rua ki te \frac{2}{15}.

$$y=\frac{\frac{1}{5}}{\frac{2}{15}}$$

Tuhia te \frac{\frac{1}{5}}{\frac{2}{15}} hei hautanga kotahi.

$$y=\frac{1}{5\times \frac{2}{15}}$$

Whakareatia te 5 ki te \frac{2}{15}, ka \frac{2}{3}.

$$y=\frac{1}{\frac{2}{3}}$$