Whakaoti i te -x^4(2xyz^2)^0/x^2

$$\frac { - x ^ { 4 } ( 2 x y z ^ { 2 } ) ^ { 0 } } { x ^ { 2 } }$$

Aromātai

$$-x^{2}$$

Ngā Hipanga Rongoā Poto

Tātaihia te 2xyz^{2} mā te pū o 0, kia riro ko 1.

$$\frac{\left(-x^{4}\right)\times 1}{x^{2}}$$

Me whakatauwehe ngā kīanga kāore anō i whakatauwehea.

$$\frac{-x^{4}}{x^{2}}$$

Me whakakore tahi te x^{2} i te taurunga me te tauraro.

$$-x^{2}$$

Kimi Pārōnaki e ai ki x

$$-2x$$

Ngā Upane e Whakamahi ana i te Tautuhinga o te Pārōnaki

Tātaihia te 2xyz^{2} mā te pū o 0, kia riro ko 1.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{\left(-x^{4}\right)\times 1}{x^{2}})$$

Me whakatauwehe ngā kīanga kāore anō i whakatauwehea i roto o \frac{\left(-x^{4}\right)\times 1}{x^{2}}.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{-x^{4}}{x^{2}})$$

Me whakakore tahi te x^{2} i te taurunga me te tauraro.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-x^{2})$$

Ko te pārōnaki o ax^{n} ko nax^{n-1}.

$$2\left(-1\right)x^{2-1}$$

Whakareatia 2 ki te -1.

$$-2x^{2-1}$$

Tango 1 mai i 2.

$$-2x^{1}$$

Mō tētahi kupu t, t^{1}=t.

$$-2x$$