Whakaoti i te -7x-7/3x+8>-1

$$\frac { - 7 x - 7 } { 3 x + 8 } > - 1$$

Whakaoti mō x

$$x\in \left(-\frac{8}{3},\frac{1}{4}\right)$$

Ngā Upane Otinga

Kāore e taea a te tauraro 3x+8 te numa kore nā te mea kāore te rituatanga mā te kore e tautuhi. E rua ngā kēhi.

$$3x+8>0 3x+8<0$$

Whakaarohia te kēhi i ngā wā kei te tōrunga a 3x+8. Neke atu a 8 ki te taha matau.

$$3x>-8$$

Whakawehea ngā taha e rua ki te 3. I te mea he tōrunga te 3, kāore e huri te ahunga koreōrite.

$$x>-\frac{8}{3}$$

Kāore te tōrite tuatahi e whakarerekē te aronga ina e whakarea ana mā 3x+8 mō 3x+8>0.

$$-7x-7>-\left(3x+8\right)$$

Whakarea te katoa o te taha matau.

$$-7x-7>-3x-8$$

Neke atu ngā kīanga tau e whai ana i x ki te taha mauī me ētahi atu kupu katoa ki te taha matau.

$$-7x+3x>7-8$$

Pahekotia ngā kīanga tau ōrite.

$$-4x>-1$$

Whakawehea ngā taha e rua ki te -4. I te mea he tōraro a -4, ka huri te ahunga koreōrite.

$$x<\frac{1}{4}$$

Whakaarohia te herenga x>-\frac{8}{3} e tautuhi ana ki runga.

$$x\in \left(-\frac{8}{3},\frac{1}{4}\right)$$

Tēnā, me whakaarohia te tauira ina e tōraro a 3x+8. Neke atu a 8 ki te taha matau.

$$3x<-8$$

Whakawehea ngā taha e rua ki te 3. I te mea he tōrunga te 3, kāore e huri te ahunga koreōrite.

$$x<-\frac{8}{3}$$

E whakarerekē ana te aronga o te tōrite tuatahi hei ngā wā e whakarea ana a 3x+8 mō 3x+8<0.

$$-7x-7<-\left(3x+8\right)$$

Whakarea te katoa o te taha matau.

$$-7x-7<-3x-8$$

Neke atu ngā kīanga tau e whai ana i x ki te taha mauī me ētahi atu kupu katoa ki te taha matau.

$$-7x+3x<7-8$$

Pahekotia ngā kīanga tau ōrite.

$$-4x<-1$$

Whakawehea ngā taha e rua ki te -4. I te mea he tōraro a -4, ka huri te ahunga koreōrite.

$$x>\frac{1}{4}$$

Whakaarohia te herenga x<-\frac{8}{3} e tautuhi ana ki runga.

$$x\in \emptyset$$

Ko te otinga whakamutunga ko te whakakotahi i ngā otinga kua whiwhi.

$$x\in \left(-\frac{8}{3},\frac{1}{4}\right)$$