Whakaoti i te (x-1)^2/4x^2-1*2x^2-3x-2/x^2-4x+3

$$\frac { ( x - 1 ) ^ { 2 } } { 4 x ^ { 2 } - 1 } \times \frac { 2 x ^ { 2 } - 3 x - 2 } { x ^ { 2 } - 4 x + 3 }$$

Aromātai

$$\frac{\left(x-2\right)\left(x-1\right)}{\left(x-3\right)\left(2x-1\right)}$$

Ngā Hipanga Rongoā Poto

Me whakarea te \frac{\left(x-1\right)^{2}}{4x^{2}-1} ki te \frac{2x^{2}-3x-2}{x^{2}-4x+3} mā te whakarea taurunga ki te taurunga me te tauraro ki te tauraro.

$$\frac{\left(x-1\right)^{2}\left(2x^{2}-3x-2\right)}{\left(4x^{2}-1\right)\left(x^{2}-4x+3\right)}$$

Me whakatauwehe ngā kīanga kāore anō i whakatauwehea.

$$\frac{\left(x-2\right)\left(2x+1\right)\left(x-1\right)^{2}}{\left(x-3\right)\left(x-1\right)\left(2x-1\right)\left(2x+1\right)}$$

Me whakakore tahi te \left(x-1\right)\left(2x+1\right) i te taurunga me te tauraro.

$$\frac{\left(x-2\right)\left(x-1\right)}{\left(x-3\right)\left(2x-1\right)}$$

Me whakaroha te kīanga.

$$\frac{x^{2}-3x+2}{2x^{2}-7x+3}$$

Whakaroha

$$\frac{x^{2}-3x+2}{\left(x-3\right)\left(2x-1\right)}$$

Ngā Hipanga Rongoā Poto

Me whakarea te \frac{\left(x-1\right)^{2}}{4x^{2}-1} ki te \frac{2x^{2}-3x-2}{x^{2}-4x+3} mā te whakarea taurunga ki te taurunga me te tauraro ki te tauraro.

$$\frac{\left(x-1\right)^{2}\left(2x^{2}-3x-2\right)}{\left(4x^{2}-1\right)\left(x^{2}-4x+3\right)}$$

Me whakatauwehe ngā kīanga kāore anō i whakatauwehea.

$$\frac{\left(x-2\right)\left(2x+1\right)\left(x-1\right)^{2}}{\left(x-3\right)\left(x-1\right)\left(2x-1\right)\left(2x+1\right)}$$

Me whakakore tahi te \left(x-1\right)\left(2x+1\right) i te taurunga me te tauraro.

$$\frac{\left(x-2\right)\left(x-1\right)}{\left(x-3\right)\left(2x-1\right)}$$

Me whakaroha te kīanga.

$$\frac{x^{2}-3x+2}{2x^{2}-7x+3}$$