Whakaoti i te (x+3)^2/2=-1/3

$$\frac { ( x + 3 ) ^ { 2 } } { 2 } = \frac { - 1 } { 3 }$$

Whakaoti mō x (complex solution)

$$x=-\frac{\sqrt{6}i}{3}-3\approx -3-0.816496581i$$

$$x=\frac{\sqrt{6}i}{3}-3\approx -3+0.816496581i$$

Ngā Upane mā te Kimi Pūtakerua

Mā te whakawehe ki te \frac{1}{2} ka wetekia te whakareanga ki te \frac{1}{2}.

$$\left(x+3\right)^{2}=-\frac{\frac{1}{3}}{\frac{1}{2}}$$

Whakawehe -\frac{1}{3} ki te \frac{1}{2} mā te whakarea -\frac{1}{3} ki te tau huripoki o \frac{1}{2}.

$$\left(x+3\right)^{2}=-\frac{2}{3}$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$x+3=\frac{\sqrt{6}i}{3} x+3=-\frac{\sqrt{6}i}{3}$$

Me tango 3 mai i ngā taha e rua o te whārite.

$$x+3-3=\frac{\sqrt{6}i}{3}-3 x+3-3=-\frac{\sqrt{6}i}{3}-3$$

Mā te tango i te 3 i a ia ake anō ka toe ko te 0.

$$x=\frac{\sqrt{6}i}{3}-3 x=-\frac{\sqrt{6}i}{3}-3$$