Whakaoti i te (2x+3)-(5x-7)/6x+11=-8/3

$$\frac { ( 2 x + 3 ) - ( 5 x - 7 ) } { 6 x + 11 } = \frac { - 8 } { 3 }$$

Whakaoti mō x

$$x = -\frac{118}{39} = -3\frac{1}{39} \approx -3.025641026$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tē taea kia ōrite te tāupe x ki -\frac{11}{6} nā te kore tautuhi i te whakawehenga mā te kore. Me whakarea ngā taha e rua o te whārite ki te 3\left(6x+11\right), arā, te tauraro pātahi he tino iti rawa te kitea o 6x+11,3.

$$3\left(2x+3-\left(5x-7\right)\right)=\left(6x+11\right)\left(-8\right)$$

Hei kimi i te tauaro o 5x-7, kimihia te tauaro o ia taurangi.

$$3\left(2x+3-5x+7\right)=\left(6x+11\right)\left(-8\right)$$

Pahekotia te 2x me -5x, ka -3x.

$$3\left(-3x+3+7\right)=\left(6x+11\right)\left(-8\right)$$

Tāpirihia te 3 ki te 7, ka 10.

$$3\left(-3x+10\right)=\left(6x+11\right)\left(-8\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te 3 ki te -3x+10.

$$-9x+30=\left(6x+11\right)\left(-8\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te 6x+11 ki te -8.

$$-9x+30=-48x-88$$

Me tāpiri te 48x ki ngā taha e rua.

$$-9x+30+48x=-88$$

Pahekotia te -9x me 48x, ka 39x.

$$39x+30=-88$$

Tangohia te 30 mai i ngā taha e rua.

$$39x=-88-30$$

Tangohia te 30 i te -88, ka -118.

$$39x=-118$$

Whakawehea ngā taha e rua ki te 39.

$$x=\frac{-118}{39}$$

Ka taea te hautanga \frac{-118}{39} te tuhi anō ko -\frac{118}{39} mā te tango i te tohu tōraro.

$$x=-\frac{118}{39}$$