Whakaoti i te (2-i)^2/(2+i)^2

$$\frac { ( 2 - i ) ^ { 2 } } { ( 2 + i ) ^ { 2 } }$$

Aromātai

$$-\frac{7}{25}-\frac{24}{25}i=-0.28-0.96i$$

Ngā Upane Otinga

Tātaihia te 2-i mā te pū o 2, kia riro ko 3-4i.

$$\frac{3-4i}{\left(2+i\right)^{2}}$$

Tātaihia te 2+i mā te pū o 2, kia riro ko 3+4i.

$$\frac{3-4i}{3+4i}$$

Whakareatia te taurunga me te tauraro ki te haumi hiato o te tauraro, 3-4i.

$$\frac{\left(3-4i\right)\left(3-4i\right)}{\left(3+4i\right)\left(3-4i\right)}$$

Mahia ngā whakarea i roto o \frac{\left(3-4i\right)\left(3-4i\right)}{\left(3+4i\right)\left(3-4i\right)}.

$$\frac{-7-24i}{25}$$

Whakawehea te -7-24i ki te 25, kia riro ko -\frac{7}{25}-\frac{24}{25}i.

$$-\frac{7}{25}-\frac{24}{25}i$$

Wāhi Tūturu

$$-\frac{7}{25} = -0.28$$

Ngā Upane Otinga

Tātaihia te 2-i mā te pū o 2, kia riro ko 3-4i.

$$Re(\frac{3-4i}{\left(2+i\right)^{2}})$$

Tātaihia te 2+i mā te pū o 2, kia riro ko 3+4i.

$$Re(\frac{3-4i}{3+4i})$$

Me whakarea te taurunga me te tauraro o \frac{3-4i}{3+4i} ki te haumi hiato o te tauraro, 3-4i.

$$Re(\frac{\left(3-4i\right)\left(3-4i\right)}{\left(3+4i\right)\left(3-4i\right)})$$

Mahia ngā whakarea i roto o \frac{\left(3-4i\right)\left(3-4i\right)}{\left(3+4i\right)\left(3-4i\right)}.

$$Re(\frac{-7-24i}{25})$$

Whakawehea te -7-24i ki te 25, kia riro ko -\frac{7}{25}-\frac{24}{25}i.

$$Re(-\frac{7}{25}-\frac{24}{25}i)$$

Ko te wāhi tūturu o -\frac{7}{25}-\frac{24}{25}i ko -\frac{7}{25}.

$$-\frac{7}{25}$$