Whakaoti i te (n+2/n-2)^3/frac{n^3+4n^2+4n{3n^2-12n+12}}*n/3

$$\frac { ( \frac { n + 2 } { n - 2 } ) ^ { 3 } } { \frac { n ^ { 3 } + 4 n ^ { 2 } + 4 n } { 3 n ^ { 2 } - 12 n + 12 } } \cdot \frac { n } { 3 }$$

Aromātai

$$\frac{n+2}{n-2}$$

Ngā Hipanga Rongoā Poto

Kia whakarewa i te \frac{n+2}{n-2} ki tētahi taupū, me whakarewa tahi te taurunga me te tauraro ki te taupū kātahi ka whakawehe.

$$\frac{\frac{\left(n+2\right)^{3}}{\left(n-2\right)^{3}}}{\frac{n^{3}+4n^{2}+4n}{3n^{2}-12n+12}}\times \frac{n}{3}$$

Whakawehe \frac{\left(n+2\right)^{3}}{\left(n-2\right)^{3}} ki te \frac{n^{3}+4n^{2}+4n}{3n^{2}-12n+12} mā te whakarea \frac{\left(n+2\right)^{3}}{\left(n-2\right)^{3}} ki te tau huripoki o \frac{n^{3}+4n^{2}+4n}{3n^{2}-12n+12}.

$$\frac{\left(n+2\right)^{3}\left(3n^{2}-12n+12\right)}{\left(n-2\right)^{3}\left(n^{3}+4n^{2}+4n\right)}\times \frac{n}{3}$$

Me whakatauwehe ngā kīanga kāore anō i whakatauwehea i roto o \frac{\left(n+2\right)^{3}\left(3n^{2}-12n+12\right)}{\left(n-2\right)^{3}\left(n^{3}+4n^{2}+4n\right)}.

$$\frac{3\left(n-2\right)^{2}\left(n+2\right)^{3}}{n\left(n+2\right)^{2}\left(n-2\right)^{3}}\times \frac{n}{3}$$

Me whakakore tahi te \left(n-2\right)^{2}\left(n+2\right)^{2} i te taurunga me te tauraro.

$$\frac{3\left(n+2\right)}{n\left(n-2\right)}\times \frac{n}{3}$$

Me whakarea te \frac{3\left(n+2\right)}{n\left(n-2\right)} ki te \frac{n}{3} mā te whakarea taurunga ki te taurunga me te tauraro ki te tauraro.

$$\frac{3\left(n+2\right)n}{n\left(n-2\right)\times 3}$$

Me whakakore tahi te 3n i te taurunga me te tauraro.

$$\frac{n+2}{n-2}$$

Whakaroha

$$\frac{n+2}{n-2}$$

Ngā Hipanga Rongoā Poto

Kia whakarewa i te \frac{n+2}{n-2} ki tētahi taupū, me whakarewa tahi te taurunga me te tauraro ki te taupū kātahi ka whakawehe.

$$\frac{\frac{\left(n+2\right)^{3}}{\left(n-2\right)^{3}}}{\frac{n^{3}+4n^{2}+4n}{3n^{2}-12n+12}}\times \frac{n}{3}$$

Whakawehe \frac{\left(n+2\right)^{3}}{\left(n-2\right)^{3}} ki te \frac{n^{3}+4n^{2}+4n}{3n^{2}-12n+12} mā te whakarea \frac{\left(n+2\right)^{3}}{\left(n-2\right)^{3}} ki te tau huripoki o \frac{n^{3}+4n^{2}+4n}{3n^{2}-12n+12}.

$$\frac{\left(n+2\right)^{3}\left(3n^{2}-12n+12\right)}{\left(n-2\right)^{3}\left(n^{3}+4n^{2}+4n\right)}\times \frac{n}{3}$$

Me whakatauwehe ngā kīanga kāore anō i whakatauwehea i roto o \frac{\left(n+2\right)^{3}\left(3n^{2}-12n+12\right)}{\left(n-2\right)^{3}\left(n^{3}+4n^{2}+4n\right)}.

$$\frac{3\left(n-2\right)^{2}\left(n+2\right)^{3}}{n\left(n+2\right)^{2}\left(n-2\right)^{3}}\times \frac{n}{3}$$

Me whakakore tahi te \left(n-2\right)^{2}\left(n+2\right)^{2} i te taurunga me te tauraro.

$$\frac{3\left(n+2\right)}{n\left(n-2\right)}\times \frac{n}{3}$$

Me whakarea te \frac{3\left(n+2\right)}{n\left(n-2\right)} ki te \frac{n}{3} mā te whakarea taurunga ki te taurunga me te tauraro ki te tauraro.

$$\frac{3\left(n+2\right)n}{n\left(n-2\right)\times 3}$$

Me whakakore tahi te 3n i te taurunga me te tauraro.

$$\frac{n+2}{n-2}$$