Whakaoti i te frac{(frac{sqrt{3}}{1})^{2}+4*(1/sqrt{2})^2+3*(2/sqrt{3})^2+5*0^2}{2+2-(sqrt{3})^2}

$$\frac { ( \frac { \sqrt { 3 } } { 1 } ) ^ { 2 } + 4 \times ( \frac { 1 } { \sqrt { 2 } } ) ^ { 2 } + 3 \times ( \frac { 2 } { \sqrt { 3 } } ) ^ { 2 } + 5 \times 0 ^ { 2 } } { 2 + 2 - ( \sqrt { 3 } ) ^ { 2 } }$$

Aromātai

$$9$$

Ngā Upane Otinga

Ka whakawehea he tau ki te tahi, hua ai ko ia anō.

$$\frac{\left(\sqrt{3}\right)^{2}+4\times \left(\frac{1}{\sqrt{2}}\right)^{2}+3\times \left(\frac{2}{\sqrt{3}}\right)^{2}+5\times 0^{2}}{2+2-\left(\sqrt{3}\right)^{2}}$$

Ko te pūrua o \sqrt{3} ko 3.

$$\frac{3+4\times \left(\frac{1}{\sqrt{2}}\right)^{2}+3\times \left(\frac{2}{\sqrt{3}}\right)^{2}+5\times 0^{2}}{2+2-\left(\sqrt{3}\right)^{2}}$$

Whakangāwaritia te tauraro o \frac{1}{\sqrt{2}} mā te whakarea i te taurunga me te tauraro ki te \sqrt{2}.

$$\frac{3+4\times \left(\frac{\sqrt{2}}{\left(\sqrt{2}\right)^{2}}\right)^{2}+3\times \left(\frac{2}{\sqrt{3}}\right)^{2}+5\times 0^{2}}{2+2-\left(\sqrt{3}\right)^{2}}$$

Ko te pūrua o \sqrt{2} ko 2.

$$\frac{3+4\times \left(\frac{\sqrt{2}}{2}\right)^{2}+3\times \left(\frac{2}{\sqrt{3}}\right)^{2}+5\times 0^{2}}{2+2-\left(\sqrt{3}\right)^{2}}$$

Kia whakarewa i te \frac{\sqrt{2}}{2} ki tētahi taupū, me whakarewa tahi te taurunga me te tauraro ki te taupū kātahi ka whakawehe.

$$\frac{3+4\times \frac{\left(\sqrt{2}\right)^{2}}{2^{2}}+3\times \left(\frac{2}{\sqrt{3}}\right)^{2}+5\times 0^{2}}{2+2-\left(\sqrt{3}\right)^{2}}$$

Tuhia te 4\times \frac{\left(\sqrt{2}\right)^{2}}{2^{2}} hei hautanga kotahi.

$$\frac{3+\frac{4\left(\sqrt{2}\right)^{2}}{2^{2}}+3\times \left(\frac{2}{\sqrt{3}}\right)^{2}+5\times 0^{2}}{2+2-\left(\sqrt{3}\right)^{2}}$$

Whakangāwaritia te tauraro o \frac{2}{\sqrt{3}} mā te whakarea i te taurunga me te tauraro ki te \sqrt{3}.

$$\frac{3+\frac{4\left(\sqrt{2}\right)^{2}}{2^{2}}+3\times \left(\frac{2\sqrt{3}}{\left(\sqrt{3}\right)^{2}}\right)^{2}+5\times 0^{2}}{2+2-\left(\sqrt{3}\right)^{2}}$$

Ko te pūrua o \sqrt{3} ko 3.

$$\frac{3+\frac{4\left(\sqrt{2}\right)^{2}}{2^{2}}+3\times \left(\frac{2\sqrt{3}}{3}\right)^{2}+5\times 0^{2}}{2+2-\left(\sqrt{3}\right)^{2}}$$

Kia whakarewa i te \frac{2\sqrt{3}}{3} ki tētahi taupū, me whakarewa tahi te taurunga me te tauraro ki te taupū kātahi ka whakawehe.

$$\frac{3+\frac{4\left(\sqrt{2}\right)^{2}}{2^{2}}+3\times \frac{\left(2\sqrt{3}\right)^{2}}{3^{2}}+5\times 0^{2}}{2+2-\left(\sqrt{3}\right)^{2}}$$

Tuhia te 3\times \frac{\left(2\sqrt{3}\right)^{2}}{3^{2}} hei hautanga kotahi.

$$\frac{3+\frac{4\left(\sqrt{2}\right)^{2}}{2^{2}}+\frac{3\times \left(2\sqrt{3}\right)^{2}}{3^{2}}+5\times 0^{2}}{2+2-\left(\sqrt{3}\right)^{2}}$$

Me whakakore tahi te 3 i te taurunga me te tauraro.

$$\frac{3+\frac{4\left(\sqrt{2}\right)^{2}}{2^{2}}+\frac{\left(2\sqrt{3}\right)^{2}}{3}+5\times 0^{2}}{2+2-\left(\sqrt{3}\right)^{2}}$$

Tātaihia te 0 mā te pū o 2, kia riro ko 0.

$$\frac{3+\frac{4\left(\sqrt{2}\right)^{2}}{2^{2}}+\frac{\left(2\sqrt{3}\right)^{2}}{3}+5\times 0}{2+2-\left(\sqrt{3}\right)^{2}}$$

Whakareatia te 5 ki te 0, ka 0.

$$\frac{3+\frac{4\left(\sqrt{2}\right)^{2}}{2^{2}}+\frac{\left(2\sqrt{3}\right)^{2}}{3}+0}{2+2-\left(\sqrt{3}\right)^{2}}$$

Tāpirihia te 3 ki te 0, ka 3.

$$\frac{3+\frac{4\left(\sqrt{2}\right)^{2}}{2^{2}}+\frac{\left(2\sqrt{3}\right)^{2}}{3}}{2+2-\left(\sqrt{3}\right)^{2}}$$

Whakarohaina te \left(2\sqrt{3}\right)^{2}.

$$\frac{3+\frac{4\left(\sqrt{2}\right)^{2}}{2^{2}}+\frac{2^{2}\left(\sqrt{3}\right)^{2}}{3}}{2+2-\left(\sqrt{3}\right)^{2}}$$

Tātaihia te 2 mā te pū o 2, kia riro ko 4.

$$\frac{3+\frac{4\left(\sqrt{2}\right)^{2}}{2^{2}}+\frac{4\left(\sqrt{3}\right)^{2}}{3}}{2+2-\left(\sqrt{3}\right)^{2}}$$

Ko te pūrua o \sqrt{3} ko 3.

$$\frac{3+\frac{4\left(\sqrt{2}\right)^{2}}{2^{2}}+\frac{4\times 3}{3}}{2+2-\left(\sqrt{3}\right)^{2}}$$

Whakareatia te 4 ki te 3, ka 12.

$$\frac{3+\frac{4\left(\sqrt{2}\right)^{2}}{2^{2}}+\frac{12}{3}}{2+2-\left(\sqrt{3}\right)^{2}}$$

Whakawehea te 12 ki te 3, kia riro ko 4.

$$\frac{3+\frac{4\left(\sqrt{2}\right)^{2}}{2^{2}}+4}{2+2-\left(\sqrt{3}\right)^{2}}$$

Tāpirihia te 3 ki te 4, ka 7.

$$\frac{7+\frac{4\left(\sqrt{2}\right)^{2}}{2^{2}}}{2+2-\left(\sqrt{3}\right)^{2}}$$

Ko te pūrua o \sqrt{2} ko 2.

$$\frac{7+\frac{4\times 2}{2^{2}}}{2+2-\left(\sqrt{3}\right)^{2}}$$

Whakareatia te 4 ki te 2, ka 8.

$$\frac{7+\frac{8}{2^{2}}}{2+2-\left(\sqrt{3}\right)^{2}}$$

Tātaihia te 2 mā te pū o 2, kia riro ko 4.

$$\frac{7+\frac{8}{4}}{2+2-\left(\sqrt{3}\right)^{2}}$$

Whakawehea te 8 ki te 4, kia riro ko 2.

$$\frac{7+2}{2+2-\left(\sqrt{3}\right)^{2}}$$

Tāpirihia te 7 ki te 2, ka 9.

$$\frac{9}{2+2-\left(\sqrt{3}\right)^{2}}$$

Tāpirihia te 2 ki te 2, ka 4.

$$\frac{9}{4-\left(\sqrt{3}\right)^{2}}$$

Ko te pūrua o \sqrt{3} ko 3.

$$\frac{9}{4-3}$$

Tangohia te 3 i te 4, ka 1.

$$\frac{9}{1}$$

Ka whakawehea he tau ki te tahi, hua ai ko ia anō.

$$9$$

Tauwehe

$$3^{2}$$