Whakaoti i te frac{text{Cup}}{mm}quad1/5=274/14

$$\frac { \text { Cup } } { m m } \quad 1 / 5 = \frac { 274 } { 14 }$$

Whakaoti mō C

$$C=\frac{685m^{2}}{7pu}$$

$$p\neq 0\text{ and }u\neq 0\text{ and }m\neq 0$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Me whakarea ngā taha e rua o te whārite ki te 70m^{2}, arā, te tauraro pātahi he tino iti rawa te kitea o mm,5,14.

$$70Cup\times \frac{1}{5}=5m^{2}\times 274$$

Whakareatia te 70 ki te \frac{1}{5}, ka 14.

$$14Cup=5m^{2}\times 274$$

Whakareatia te 5 ki te 274, ka 1370.

$$14Cup=1370m^{2}$$

He hanga arowhānui tō te whārite.

$$14puC=1370m^{2}$$

Whakawehea ngā taha e rua ki te 14up.

$$\frac{14puC}{14pu}=\frac{1370m^{2}}{14pu}$$

Mā te whakawehe ki te 14up ka wetekia te whakareanga ki te 14up.

$$C=\frac{1370m^{2}}{14pu}$$

Whakawehe 1370m^{2} ki te 14up.

$$C=\frac{685m^{2}}{7pu}$$

Whakaoti mō m (complex solution)

$$m=-\frac{\sqrt{C}\sqrt{u}\sqrt{4795p}}{685}$$

$$m=\frac{\sqrt{C}\sqrt{u}\sqrt{4795p}}{685}\text{, }p\neq 0\text{ and }u\neq 0\text{ and }C\neq 0$$

Whakaoti mō m

$$m=\frac{\sqrt{4795Cpu}}{685}$$

$$m=-\frac{\sqrt{4795Cpu}}{685}\text{, }\left(C<0\text{ and }p<0\text{ and }u>0\right)\text{ or }\left(p>0\text{ and }C>0\text{ and }u>0\right)\text{ or }\left(u<0\text{ and }p<0\text{ and }C>0\right)\text{ or }\left(u<0\text{ and }C<0\text{ and }p>0\right)$$