Whakaoti i te frac{sqrt{6}-sqrt{2}}{4}*frac{sqrt{6}-1sqrt{2}}{4}

$$\frac { \sqrt { 6 } - \sqrt { 2 } } { 4 } \times \frac { \sqrt { 6 } - 1 \sqrt { 2 } } { 4 }$$

Aromātai

$$-\frac{\sqrt{3}}{4}+\frac{1}{2}\approx 0.066987298$$

Ngā Upane Otinga

Whakareatia te \frac{\sqrt{6}-\sqrt{2}}{4} ki te \frac{\sqrt{6}-\sqrt{2}}{4}, ka \left(\frac{\sqrt{6}-\sqrt{2}}{4}\right)^{2}.

$$\left(\frac{\sqrt{6}-\sqrt{2}}{4}\right)^{2}$$

Kia whakarewa i te \frac{\sqrt{6}-\sqrt{2}}{4} ki tētahi taupū, me whakarewa tahi te taurunga me te tauraro ki te taupū kātahi ka whakawehe.

$$\frac{\left(\sqrt{6}-\sqrt{2}\right)^{2}}{4^{2}}$$

Whakamahia te ture huarua \left(a-b\right)^{2}=a^{2}-2ab+b^{2} hei whakaroha \left(\sqrt{6}-\sqrt{2}\right)^{2}.

$$\frac{\left(\sqrt{6}\right)^{2}-2\sqrt{6}\sqrt{2}+\left(\sqrt{2}\right)^{2}}{4^{2}}$$

Ko te pūrua o \sqrt{6} ko 6.

$$\frac{6-2\sqrt{6}\sqrt{2}+\left(\sqrt{2}\right)^{2}}{4^{2}}$$

Tauwehea te 6=2\times 3. Tuhia anō te pūtake rua o te hua \sqrt{2\times 3} hei hua o ngā pūtake rua \sqrt{2}\sqrt{3}.

$$\frac{6-2\sqrt{2}\sqrt{3}\sqrt{2}+\left(\sqrt{2}\right)^{2}}{4^{2}}$$

Whakareatia te \sqrt{2} ki te \sqrt{2}, ka 2.

$$\frac{6-2\times 2\sqrt{3}+\left(\sqrt{2}\right)^{2}}{4^{2}}$$

Whakareatia te -2 ki te 2, ka -4.

$$\frac{6-4\sqrt{3}+\left(\sqrt{2}\right)^{2}}{4^{2}}$$

Ko te pūrua o \sqrt{2} ko 2.

$$\frac{6-4\sqrt{3}+2}{4^{2}}$$

Tāpirihia te 6 ki te 2, ka 8.

$$\frac{8-4\sqrt{3}}{4^{2}}$$

Tātaihia te 4 mā te pū o 2, kia riro ko 16.

$$\frac{8-4\sqrt{3}}{16}$$

Tauwehe

$$\frac{2 - \sqrt{3}}{4} = 0.0669872981077807$$