Whakaoti i te frac{sqrt{3}}{4}x(-3/2x+24)

$$\frac { \sqrt { 3 } } { 4 } x ( - \frac { 3 } { 2 } x + 24 )$$

Aromātai

$$\frac{3\sqrt{3}x\left(16-x\right)}{8}$$

Ngā Hipanga Rongoā Poto

Tuhia te \frac{\sqrt{3}}{4}x hei hautanga kotahi.

$$\frac{\sqrt{3}x}{4}\left(-\frac{3}{2}x+24\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te \frac{\sqrt{3}x}{4} ki te -\frac{3}{2}x+24.

$$\frac{\sqrt{3}x}{4}\left(-\frac{3}{2}\right)x+24\times \frac{\sqrt{3}x}{4}$$

Me whakarea te \frac{\sqrt{3}x}{4} ki te -\frac{3}{2} mā te whakarea taurunga ki te taurunga me te tauraro ki te tauraro.

$$\frac{-\sqrt{3}x\times 3}{4\times 2}x+24\times \frac{\sqrt{3}x}{4}$$

Tuhia te \frac{-\sqrt{3}x\times 3}{4\times 2}x hei hautanga kotahi.

$$\frac{-\sqrt{3}x\times 3x}{4\times 2}+24\times \frac{\sqrt{3}x}{4}$$

Whakakorea atu te tauwehe pūnoa nui rawa 4 i roto i te 24 me te 4.

$$\frac{-\sqrt{3}x\times 3x}{4\times 2}+6\sqrt{3}x$$

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Whakareatia 6\sqrt{3}x ki te \frac{4\times 2}{4\times 2}.

$$\frac{-\sqrt{3}x\times 3x}{4\times 2}+\frac{6\sqrt{3}x\times 4\times 2}{4\times 2}$$

Tā te mea he rite te tauraro o \frac{-\sqrt{3}x\times 3x}{4\times 2} me \frac{6\sqrt{3}x\times 4\times 2}{4\times 2}, me tāpiri rāua mā te tāpiri i ō raua taurunga.

$$\frac{-\sqrt{3}x\times 3x+6\sqrt{3}x\times 4\times 2}{4\times 2}$$

Mahia ngā whakarea i roto o -\sqrt{3}x\times 3x+6\sqrt{3}x\times 4\times 2.

$$\frac{-3\sqrt{3}x^{2}+48\sqrt{3}x}{4\times 2}$$

Whakarohaina te 4\times 2.

$$\frac{-3\sqrt{3}x^{2}+48\sqrt{3}x}{8}$$

Tauwehe

$$\frac{3\sqrt{3}x\left(16-x\right)}{8}$$