Whakaoti i te frac{sqrt{3}+sqrt{3}}{sqrt{2}-1}

$$\frac { \sqrt { 3 } + \sqrt { 3 } } { \sqrt { 2 } - 1 }$$

Aromātai

$$2\sqrt{3}\left(\sqrt{2}+1\right)\approx 8.363081101$$

Ngā Upane Otinga

Pahekotia te \sqrt{3} me \sqrt{3}, ka 2\sqrt{3}.

$$\frac{2\sqrt{3}}{\sqrt{2}-1}$$

Whakangāwaritia te tauraro o \frac{2\sqrt{3}}{\sqrt{2}-1} mā te whakarea i te taurunga me te tauraro ki te \sqrt{2}+1.

$$\frac{2\sqrt{3}\left(\sqrt{2}+1\right)}{\left(\sqrt{2}-1\right)\left(\sqrt{2}+1\right)}$$

Whakaarohia te \left(\sqrt{2}-1\right)\left(\sqrt{2}+1\right). Ka taea te whakareanga te panoni ki te rerekētanga o ngā pūrua mā te ture: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

$$\frac{2\sqrt{3}\left(\sqrt{2}+1\right)}{\left(\sqrt{2}\right)^{2}-1^{2}}$$

Pūrua \sqrt{2}. Pūrua 1.

$$\frac{2\sqrt{3}\left(\sqrt{2}+1\right)}{2-1}$$

Tangohia te 1 i te 2, ka 1.

$$\frac{2\sqrt{3}\left(\sqrt{2}+1\right)}{1}$$

Ka whakawehea he tau ki te tahi, hua ai ko ia anō.

$$2\sqrt{3}\left(\sqrt{2}+1\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te 2\sqrt{3} ki te \sqrt{2}+1.

$$2\sqrt{3}\sqrt{2}+2\sqrt{3}$$

Hei whakarea \sqrt{3} me \sqrt{2}, whakareatia ngā tau i raro i te pūtake rua.

$$2\sqrt{6}+2\sqrt{3}$$

Tauwehe

$$2 \sqrt{3} {(\sqrt{2} + 1)} = 8.363081101$$