Whakaoti i te frac{sqrt{2}a}{(sqrt{2}-1)a}

$$\frac { \sqrt { 2 } a } { ( \sqrt { 2 } - 1 ) a }$$

Aromātai

$$\sqrt{2}+2\approx 3.414213562$$

Ngā Upane Otinga

Me whakakore tahi te a i te taurunga me te tauraro.

$$\frac{\sqrt{2}}{\sqrt{2}-1}$$

Whakangāwaritia te tauraro o \frac{\sqrt{2}}{\sqrt{2}-1} mā te whakarea i te taurunga me te tauraro ki te \sqrt{2}+1.

$$\frac{\sqrt{2}\left(\sqrt{2}+1\right)}{\left(\sqrt{2}-1\right)\left(\sqrt{2}+1\right)}$$

Whakaarohia te \left(\sqrt{2}-1\right)\left(\sqrt{2}+1\right). Ka taea te whakareanga te panoni ki te rerekētanga o ngā pūrua mā te ture: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

$$\frac{\sqrt{2}\left(\sqrt{2}+1\right)}{\left(\sqrt{2}\right)^{2}-1^{2}}$$

Pūrua \sqrt{2}. Pūrua 1.

$$\frac{\sqrt{2}\left(\sqrt{2}+1\right)}{2-1}$$

Tangohia te 1 i te 2, ka 1.

$$\frac{\sqrt{2}\left(\sqrt{2}+1\right)}{1}$$

Ka whakawehea he tau ki te tahi, hua ai ko ia anō.

$$\sqrt{2}\left(\sqrt{2}+1\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te \sqrt{2} ki te \sqrt{2}+1.

$$\left(\sqrt{2}\right)^{2}+\sqrt{2}$$

Ko te pūrua o \sqrt{2} ko 2.

$$2+\sqrt{2}$$