Whakaoti i te 17/16k^4+49/64k^2+1/8/k^2+frac{1{4}}

$$\frac { \frac { 17 } { 16 } k ^ { 4 } + \frac { 49 } { 64 } k ^ { 2 } + \frac { 1 } { 8 } } { k ^ { 2 } + \frac { 1 } { 4 } }$$

Aromātai

$$\frac{17k^{2}}{16}+\frac{1}{2}$$

Ngā Hipanga Rongoā Poto

Me whakatauwehe ngā kīanga kāore anō i whakatauwehea.

$$\frac{\frac{1}{64}\left(4k^{2}+1\right)\left(17k^{2}+8\right)}{\frac{1}{4}\left(4k^{2}+1\right)}$$

Me whakakore tahi te 4k^{2}+1 i te taurunga me te tauraro.

$$\frac{\frac{1}{64}\left(17k^{2}+8\right)}{\frac{1}{4}}$$

Me whakaroha te kīanga.

$$\frac{\frac{17}{64}k^{2}+\frac{1}{8}}{\frac{1}{4}}$$

Whakawehe \frac{17}{64}k^{2}+\frac{1}{8} ki te \frac{1}{4} mā te whakarea \frac{17}{64}k^{2}+\frac{1}{8} ki te tau huripoki o \frac{1}{4}.

$$\left(\frac{17}{64}k^{2}+\frac{1}{8}\right)\times 4$$

Whakamahia te āhuatanga tohatoha hei whakarea te \frac{17}{64}k^{2}+\frac{1}{8} ki te 4.

$$\frac{17}{16}k^{2}+\frac{1}{2}$$

Whakaroha

$$\frac{17k^{2}}{16}+\frac{1}{2}$$

Ngā Hipanga Rongoā Poto

Me whakatauwehe ngā kīanga kāore anō i whakatauwehea.

$$\frac{\frac{1}{64}\left(4k^{2}+1\right)\left(17k^{2}+8\right)}{\frac{1}{4}\left(4k^{2}+1\right)}$$

Me whakakore tahi te 4k^{2}+1 i te taurunga me te tauraro.

$$\frac{\frac{1}{64}\left(17k^{2}+8\right)}{\frac{1}{4}}$$

Me whakaroha te kīanga.

$$\frac{\frac{17}{64}k^{2}+\frac{1}{8}}{\frac{1}{4}}$$

Whakawehe \frac{17}{64}k^{2}+\frac{1}{8} ki te \frac{1}{4} mā te whakarea \frac{17}{64}k^{2}+\frac{1}{8} ki te tau huripoki o \frac{1}{4}.

$$\left(\frac{17}{64}k^{2}+\frac{1}{8}\right)\times 4$$

Whakamahia te āhuatanga tohatoha hei whakarea te \frac{17}{64}k^{2}+\frac{1}{8} ki te 4.

$$\frac{17}{16}k^{2}+\frac{1}{2}$$