Whakaoti i te [(y^3)]^5/[(y^6)]^4

$$\frac { [ ( y ^ { 3 } ) ] ^ { 5 } } { [ ( y ^ { 6 } ) ] ^ { 4 } }$$

Aromātai

$$\frac{1}{y^{9}}$$

Ngā Upane Otinga

Hei hiki pū ki tētahi pū anō, me whakarea ngā taupū. Me whakarea te 3 me te 5 kia riro ai te 15.

$$\frac{y^{15}}{\left(y^{6}\right)^{4}}$$

Hei hiki pū ki tētahi pū anō, me whakarea ngā taupū. Me whakarea te 6 me te 4 kia riro ai te 24.

$$\frac{y^{15}}{y^{24}}$$

Tuhia anō te y^{24} hei y^{15}y^{9}. Me whakakore tahi te y^{15} i te taurunga me te tauraro.

$$\frac{1}{y^{9}}$$

Kimi Pārōnaki e ai ki y

$$-\frac{9}{y^{10}}$$

Ngā Upane e Whakamahi ana i te Ture Mekameka

Hei hiki pū ki tētahi pū anō, me whakarea ngā taupū. Me whakarea te 3 me te 5 kia riro ai te 15.

$$\frac{\mathrm{d}}{\mathrm{d}y}(\frac{y^{15}}{\left(y^{6}\right)^{4}})$$

Hei hiki pū ki tētahi pū anō, me whakarea ngā taupū. Me whakarea te 6 me te 4 kia riro ai te 24.

$$\frac{\mathrm{d}}{\mathrm{d}y}(\frac{y^{15}}{y^{24}})$$

Tuhia anō te y^{24} hei y^{15}y^{9}. Me whakakore tahi te y^{15} i te taurunga me te tauraro.

$$\frac{\mathrm{d}}{\mathrm{d}y}(\frac{1}{y^{9}})$$

Mēnā ko F te hanganga o ngā pānga e rua e taea ana te pārōnaki f\left(u\right) me u=g\left(x\right), arā, mēnā ko F\left(x\right)=f\left(g\left(x\right)\right), ko te pārōnaki o F te pārōnaki o f e ai ki u whakareatia te pārōnaki o g e ai ki x, arā, \frac{\mathrm{d}}{\mathrm{d}x}(F)\left(x\right)=\frac{\mathrm{d}}{\mathrm{d}x}(f)\left(g\left(x\right)\right)\frac{\mathrm{d}}{\mathrm{d}x}(g)\left(x\right).

$$-\left(y^{9}\right)^{-1-1}\frac{\mathrm{d}}{\mathrm{d}y}(y^{9})$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$-\left(y^{9}\right)^{-2}\times 9y^{9-1}$$

Whakarūnātia.

$$-9y^{8}\left(y^{9}\right)^{-2}$$