Tīpoka ki ngā ihirangi matua
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Tohaina

\cos(-\frac{1}{4}\pi )
Pahekotia te \frac{\pi }{4} me -\frac{\pi }{2}, ka -\frac{1}{4}\pi .
\cos(\frac{1}{4}\pi )
Whakamahia te āhuatanga \cos(-x)=\cos(x).
\frac{\sqrt{2}}{2}
Tīkina te uara \cos(\frac{1}{4}\pi ) mai i te ripanga uara pākoki.