Whakaoti i te Delta=4^2-4(4-10/3)

$$\Delta = 4 ^ { 2 } - 4 ( 4 - \frac { 10 } { 3 } )$$

Whakaoti mō Δ

$$\Delta =\frac{40}{3}\approx 13.333333333$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tātaihia te 4 mā te pū o 2, kia riro ko 16.

$$\Delta =16-4\left(4-\frac{10}{3}\right)$$

Me tahuri te 4 ki te hautau \frac{12}{3}.

$$\Delta =16-4\left(\frac{12}{3}-\frac{10}{3}\right)$$

Tā te mea he rite te tauraro o \frac{12}{3} me \frac{10}{3}, me tango rāua mā te tango i ō raua taurunga.

$$\Delta =16-4\times \frac{12-10}{3}$$

Tangohia te 10 i te 12, ka 2.

$$\Delta =16-4\times \frac{2}{3}$$

Tuhia te 4\times \frac{2}{3} hei hautanga kotahi.

$$\Delta =16-\frac{4\times 2}{3}$$

Whakareatia te 4 ki te 2, ka 8.

$$\Delta =16-\frac{8}{3}$$

Me tahuri te 16 ki te hautau \frac{48}{3}.

$$\Delta =\frac{48}{3}-\frac{8}{3}$$

Tā te mea he rite te tauraro o \frac{48}{3} me \frac{8}{3}, me tango rāua mā te tango i ō raua taurunga.

$$\Delta =\frac{48-8}{3}$$

Tangohia te 8 i te 48, ka 40.

$$\Delta =\frac{40}{3}$$

Tautapa Δ

$$\Delta ≔\frac{40}{3}$$