Whakaoti i te Delta=4^2-4(4(-10/3))

$$\Delta = 4 ^ { 2 } - 4 ( 4 ( - \frac { 10 } { 3 } ) )$$

Whakaoti mō Δ

$$\Delta =\frac{208}{3}\approx 69.333333333$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tātaihia te 4 mā te pū o 2, kia riro ko 16.

$$\Delta =16-4\times 4\left(-\frac{10}{3}\right)$$

Whakareatia te 4 ki te 4, ka 16.

$$\Delta =16-16\left(-\frac{10}{3}\right)$$

Tuhia te 16\left(-\frac{10}{3}\right) hei hautanga kotahi.

$$\Delta =16-\frac{16\left(-10\right)}{3}$$

Whakareatia te 16 ki te -10, ka -160.

$$\Delta =16-\frac{-160}{3}$$

Ka taea te hautanga \frac{-160}{3} te tuhi anō ko -\frac{160}{3} mā te tango i te tohu tōraro.

$$\Delta =16-\left(-\frac{160}{3}\right)$$

Ko te tauaro o -\frac{160}{3} ko \frac{160}{3}.

$$\Delta =16+\frac{160}{3}$$

Me tahuri te 16 ki te hautau \frac{48}{3}.

$$\Delta =\frac{48}{3}+\frac{160}{3}$$

Tā te mea he rite te tauraro o \frac{48}{3} me \frac{160}{3}, me tāpiri rāua mā te tāpiri i ō raua taurunga.

$$\Delta =\frac{48+160}{3}$$

Tāpirihia te 48 ki te 160, ka 208.

$$\Delta =\frac{208}{3}$$

Tautapa Δ

$$\Delta ≔\frac{208}{3}$$