Whakaoti i te {a^{2}b^{2}c+[-1/2a^2b^2c-(-3/2a^2b^2c)]}:{-[-(abc)+(-1/8abc)]}

$$\{ a ^ { 2 } b ^ { 2 } c + [ - \frac { 1 } { 2 } a ^ { 2 } b ^ { 2 } c - ( - \frac { 3 } { 2 } a ^ { 2 } b ^ { 2 } c ) ] \} : \{ - [ - ( a b c ) + ( - \frac { 1 } { 8 } a b c ) ] \}$$

Aromātai

$$\frac{16ab}{9}$$

Ngā Hipanga Rongoā Poto

Ko te tauaro o -\frac{3}{2}a^{2}b^{2}c ko \frac{3}{2}a^{2}b^{2}c.

$$\frac{a^{2}b^{2}c-\frac{1}{2}a^{2}b^{2}c+\frac{3}{2}a^{2}b^{2}c}{-\left(-abc-\frac{1}{8}abc\right)}$$

Pahekotia te -\frac{1}{2}a^{2}b^{2}c me \frac{3}{2}a^{2}b^{2}c, ka a^{2}b^{2}c.

$$\frac{a^{2}b^{2}c+a^{2}b^{2}c}{-\left(-abc-\frac{1}{8}abc\right)}$$

Pahekotia te a^{2}b^{2}c me a^{2}b^{2}c, ka 2a^{2}b^{2}c.

$$\frac{2a^{2}b^{2}c}{-\left(-abc-\frac{1}{8}abc\right)}$$

Hei kimi i te tauaro o -abc-\frac{1}{8}abc, kimihia te tauaro o ia taurangi.

$$\frac{2a^{2}b^{2}c}{-\left(-abc\right)+\frac{1}{8}abc}$$

Me whakatauwehe ngā kīanga kāore anō i whakatauwehea.

$$\frac{2ca^{2}b^{2}}{\frac{1}{8}\left(1+8\right)abc}$$

Me whakakore tahi te abc i te taurunga me te tauraro.

$$\frac{2ab}{\frac{1}{8}\left(1+8\right)}$$

Me whakaroha te kīanga.

$$\frac{2ab}{\frac{9}{8}}$$

Whakawehe 2ab ki te \frac{9}{8} mā te whakarea 2ab ki te tau huripoki o \frac{9}{8}.

$$\frac{2ab\times 8}{9}$$

Whakareatia te 2 ki te 8, ka 16.

$$\frac{16ab}{9}$$

Whakaroha

$$\frac{16ab}{9}$$

Ngā Hipanga Rongoā Poto

Ko te tauaro o -\frac{3}{2}a^{2}b^{2}c ko \frac{3}{2}a^{2}b^{2}c.

$$\frac{a^{2}b^{2}c-\frac{1}{2}a^{2}b^{2}c+\frac{3}{2}a^{2}b^{2}c}{-\left(-abc-\frac{1}{8}abc\right)}$$

Pahekotia te -\frac{1}{2}a^{2}b^{2}c me \frac{3}{2}a^{2}b^{2}c, ka a^{2}b^{2}c.

$$\frac{a^{2}b^{2}c+a^{2}b^{2}c}{-\left(-abc-\frac{1}{8}abc\right)}$$

Pahekotia te a^{2}b^{2}c me a^{2}b^{2}c, ka 2a^{2}b^{2}c.

$$\frac{2a^{2}b^{2}c}{-\left(-abc-\frac{1}{8}abc\right)}$$

Hei kimi i te tauaro o -abc-\frac{1}{8}abc, kimihia te tauaro o ia taurangi.

$$\frac{2a^{2}b^{2}c}{-\left(-abc\right)+\frac{1}{8}abc}$$

Me whakatauwehe ngā kīanga kāore anō i whakatauwehea.

$$\frac{2ca^{2}b^{2}}{\frac{1}{8}\left(1+8\right)abc}$$

Me whakakore tahi te abc i te taurunga me te tauraro.

$$\frac{2ab}{\frac{1}{8}\left(1+8\right)}$$

Me whakaroha te kīanga.

$$\frac{2ab}{\frac{9}{8}}$$

Whakawehe 2ab ki te \frac{9}{8} mā te whakarea 2ab ki te tau huripoki o \frac{9}{8}.

$$\frac{2ab\times 8}{9}$$

Whakareatia te 2 ki te 8, ka 16.

$$\frac{16ab}{9}$$